![[02] vs Time 0.04236 0.04235 0.04234 0.04233 @ 0.04232 0.04231 Chart Area = -1E-06x + 0.0423 R2 = 0.882 0.0423 0.04229 0.042](http://img.homeworklib.com/questions/075e04a0-73b5-11ea-a07a-612c18cf4f23.png?x-oss-process=image/resize,w_560)
The slope says -1E-0.6 .....
what is that value?
Homework Answers
-1E-06 means -1*10^(-6)
Starting from number which is on left on E i.e -1,move the decimal point to six places left from -1 as the no. on right of E is -06 or -6,thus the value obtained is -0.000001 or -1*10^-6.
If the no on right of E says +06 or 6 then we would have moved six places right from -1 (the no. on the left of E)and the value would have been -1000000 or -1*10^6.
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The slope says -1E-0.6 .....
what is that value?
[02] vs Time 0.04236 0.04235 0.04234 0.04233...
59. (a) By taking the slope of the curve in Figure 2.60, verify that the velocity...
59. (a) By taking the slope of the curve in Figure 2.60, verify that the velocity of the jet car is 115 m/s at t 20 s.(b) By taking the slope of the curve at any point in Figure 2.61, verify that the jet car's acceleration is 5.0 m/s2 Position vs. Time 3500t 3000 2500 9 2000 1500t 1000t 500 0 5 10 15 20 25 30 35 Time (s) Figure 2.60 Velocity vs. Time 180 T 160 140 100...
What is a thermistor? (3pt.) A. B. What property of the thermistor changes with temperature? (2pt.) C. The figure shows temperature response measured by the thermistor. From the temperature vs time r...
What is a thermistor? (3pt.) A. B. What property of the thermistor changes with temperature? (2pt.) C. The figure shows temperature response measured by the thermistor. From the temperature vs time response, compute the 10% to 90% rise time and the 10% to 90% fall time. (5pt) 32 31 30 29 O 28 27 26 Heat Released e 25 24 23 21 19 Heat Applied 18 10 15 20 25 30 35 40 45 50 55 6065 70 75 80...
Constant Positive Accederation Recall that acceleration is the slope of the v-t graph Position vs. Time...
Constant Positive Accederation Recall that acceleration is the slope of the v-t graph Position vs. Time Time (s1 Position ml Velocity bos) 0 0.2 2.5 0.4 1.5 0.5 0.6 Velocity vs. Time 0.8 1.2 2.5 1.4 0.5 Timet s 1 1.6 Acceleration vs. Time 1.8 0.5 1.5 s utat V ut at Timet S i 5 15
Question: Find the slope and intercept for both sets of data and include the units. Thank you!
Question: Find the slope and intercept for both sets of data
and include the units. Thank you!
Table 1 (water-air) 01-02 sine3 θ.-θ incidence 20 30 40 45 48 50 60 70 80 |B5-e refraction sine IOz-0 refection 17 26 | 25 |91 40.99 .75 70 85 3 84 (8 75 42 45 78-.77 30 65 5 Table 2 (air-water) sines |θι-θ incidence IB2=e reflection 03-erefract on Isino θι-92 (5 20 30 40 45 20 15.9 30 1 20 30...
if you plotted your velocity vs time would the slope be negative, positive or zero? why?...
if you plotted your velocity vs time would the slope be negative,
positive or zero? why?
llould be a div ed Distance from start Time to get there 5 m 10 m 15 m 12.05 20 m 15
1_ in part 2 is your graph of s vs t a straight line? if not how would you describe the curve (what does...
1_ in part 2 is your graph of s vs t a straight line?
if not how would you describe the curve (what does the slope tell
about the velocity )
2_ in part 3 what does your graph of v vs the tell you about the
acceleration
70 60 50 40 30 DISTANCE (cm) 20 Time (sec) Average Time sec CONSTANT ACCELERATION TABLE 2-2 60 70 50 1. DISTANCE (crm). 40 20 30 459226226L-112 1.236 13512 26 1.235 95z...
5) Velocity vs. Time 6 0 O -1 -2 0 15 20 25 Time (s) Break...
5) Velocity vs. Time 6 0 O -1 -2 0 15 20 25 Time (s) Break the velocity vs. time graph shown into sections and use them to construct a position vs. time graph. Describe the time interval at which the graph will have a negative slope.
Plot the chart and the fitted line. What is the slope and what is its interpretation?...
Plot the chart and the fitted line. What is the slope
and what is its interpretation? (10 points)
a. 0.68; for every extra hour of exercise the person increases
weekly exercise by 1 hour
b. 0.68; more exercise pushes the cancer detection back
c. 0.68; for person who exercise zero hours a week the age of
detection is 0.68.
d. 0.68; for every weekly hour of exercise the age of detection
increases by 0.68 years
e. None of the choices....
2- Make time series scatter plots ofall five varables (five graphs) Insert trend line, equation, and...
2- Make time series scatter plots ofall five varables (five graphs) Insert trend line, equation, and R-squared. Observe graphs and provide interpretation of results. Time Series Plot of DEMAND 0.1173x+14.3 R2-0.47752 25 20 10 10 15 20 25 30 Time Period (EXPLANATION) Time Series Plot of ADV 0.0916x+5.8024 R: 0.66302 10 15 Time Period 20 25 35 (EXPLANATION) Time Series of DIFF y = 0.0163x-0.0552 R2=0.18164 0.8 0.6 0.4 比0.2 35 0.2 -0.4 0.6 0.8 Time Period (EXPLANATION)
vs. I, which you plotted in the lab magnetic Using the slope and uncertainty from the...
vs. I, which you plotted in the lab magnetic Using the slope and uncertainty from the logger pro graph of tan(0) fields," calculate the value of Bearth (in Teslas) with the error assuming that the radius of the ring is R-20cm and the number of turns is N- 5 Linear Fit for: Data Set I tan(theta) tan(theta) my+b m (Slope): 0.7482 +0.04211 35 3 2.14S b (YIntercept): -0.07427 -0.08808 Correlation: 0.9906 RMSE: 0.1365 70 #0 12 13 14 18 17...
59. (a) By taking the slope of the curve in Figure 2.60, verify that the velocity of the jet car is 115 m/s at t 20 s.(b) By taking the slope of the curve at any point in Figure 2.61, verify that the jet car's acceleration is 5.0 m/s2 Position vs. Time 3500t 3000 2500 9 2000 1500t 1000t 500 0 5 10 15 20 25 30 35 Time (s) Figure 2.60 Velocity vs. Time 180 T 160 140 100...
What is a thermistor? (3pt.) A. B. What property of the thermistor changes with temperature? (2pt.) C. The figure shows temperature response measured by the thermistor. From the temperature vs time response, compute the 10% to 90% rise time and the 10% to 90% fall time. (5pt) 32 31 30 29 O 28 27 26 Heat Released e 25 24 23 21 19 Heat Applied 18 10 15 20 25 30 35 40 45 50 55 6065 70 75 80...
Constant Positive Accederation Recall that acceleration is the slope of the v-t graph Position vs. Time Time (s1 Position ml Velocity bos) 0 0.2 2.5 0.4 1.5 0.5 0.6 Velocity vs. Time 0.8 1.2 2.5 1.4 0.5 Timet s 1 1.6 Acceleration vs. Time 1.8 0.5 1.5 s utat V ut at Timet S i 5 15
Question: Find the slope and intercept for both sets of data
and include the units. Thank you!
Table 1 (water-air) 01-02 sine3 θ.-θ incidence 20 30 40 45 48 50 60 70 80 |B5-e refraction sine IOz-0 refection 17 26 | 25 |91 40.99 .75 70 85 3 84 (8 75 42 45 78-.77 30 65 5 Table 2 (air-water) sines |θι-θ incidence IB2=e reflection 03-erefract on Isino θι-92 (5 20 30 40 45 20 15.9 30 1 20 30...
if you plotted your velocity vs time would the slope be negative,
positive or zero? why?
llould be a div ed Distance from start Time to get there 5 m 10 m 15 m 12.05 20 m 15
1_ in part 2 is your graph of s vs t a straight line?
if not how would you describe the curve (what does the slope tell
about the velocity )
2_ in part 3 what does your graph of v vs the tell you about the
acceleration
70 60 50 40 30 DISTANCE (cm) 20 Time (sec) Average Time sec CONSTANT ACCELERATION TABLE 2-2 60 70 50 1. DISTANCE (crm). 40 20 30 459226226L-112 1.236 13512 26 1.235 95z...
5) Velocity vs. Time 6 0 O -1 -2 0 15 20 25 Time (s) Break the velocity vs. time graph shown into sections and use them to construct a position vs. time graph. Describe the time interval at which the graph will have a negative slope.
Plot the chart and the fitted line. What is the slope
and what is its interpretation? (10 points)
a. 0.68; for every extra hour of exercise the person increases
weekly exercise by 1 hour
b. 0.68; more exercise pushes the cancer detection back
c. 0.68; for person who exercise zero hours a week the age of
detection is 0.68.
d. 0.68; for every weekly hour of exercise the age of detection
increases by 0.68 years
e. None of the choices....
2- Make time series scatter plots ofall five varables (five graphs) Insert trend line, equation, and R-squared. Observe graphs and provide interpretation of results. Time Series Plot of DEMAND 0.1173x+14.3 R2-0.47752 25 20 10 10 15 20 25 30 Time Period (EXPLANATION) Time Series Plot of ADV 0.0916x+5.8024 R: 0.66302 10 15 Time Period 20 25 35 (EXPLANATION) Time Series of DIFF y = 0.0163x-0.0552 R2=0.18164 0.8 0.6 0.4 比0.2 35 0.2 -0.4 0.6 0.8 Time Period (EXPLANATION)
vs. I, which you plotted in the lab magnetic Using the slope and uncertainty from the logger pro graph of tan(0) fields," calculate the value of Bearth (in Teslas) with the error assuming that the radius of the ring is R-20cm and the number of turns is N- 5 Linear Fit for: Data Set I tan(theta) tan(theta) my+b m (Slope): 0.7482 +0.04211 35 3 2.14S b (YIntercept): -0.07427 -0.08808 Correlation: 0.9906 RMSE: 0.1365 70 #0 12 13 14 18 17...
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