Question

1 Weekly hour Age of cancer detection 5.6 4.5 4.2 4.3 3.3 2.5 47.44 34.15 30.18 31.87 36.77 37.55 42.8 42.46 36.01 39.06 36.63 38.46 32.73 37.33 35.52 30.46 40.44 36.39 32.59 Age of cancer detection y 0.6752x+34.165 R2 0.0512 50 45 40 35 30 25 20 15 10 3.4 1.9 9 6.7 2.4 2.7 3.7 2.8 2.4 5.6 7.1 3.1 L8

Plot the chart and the fitted line. What is the slope and what is its interpretation? (10 points)

a. 0.68; for every extra hour of exercise the person increases weekly exercise by 1 hour

b. 0.68; more exercise pushes the cancer detection back

c. 0.68; for person who exercise zero hours a week the age of detection is 0.68.

d. 0.68; for every weekly hour of exercise the age of detection increases by 0.68 years

e. None of the choices.

Answer 1

Answer

we have the regression equation

Age of cancer detection = 0.6752x + 34.165

comparing it with general equation y = ax + b, where a is slope and b is intercept

we get, slope = 0.6752 or 0.68 and intercept = 34.165

So, it is clear that the slope is 0.68 (It is positive value)

This slope indicate that for every 1 weekly hour(unit of variable x), there is an increase of 0.68 units in the age of cancer detection

So, option D is correct answer.