1)
see experiment 2 and 1:
[I-] doubles
[OCl-] is constant
rate doubles
so, order of I- is 1
see experiment 3 and 2:
[I-] doubles. This will double the rate as order of I- is 1.
[OCl-] doubles
rate becomes 4 times.
So, rate must have doubled because of OCl- alone
so, order of OCl- is 1
overall order = 1 + 1 = 2
Rate law is:
rate = k*[I-]*[OCl-]
Answer: rate = k[I-][OCl-]
b)
rate = k*[I-]*[OCl-]
Put values from 1st row of table in rate law
rate = k*[I-]*[OCl-]
7.5*10^-2 = k*0.2*0.16
k = 2.3438 M-1.s-1
Answer: 2.34
C)
rate = k*[I-]*[OCl-]
rate =2.3438*0.13*0.13
rate = 0.0396 M/s
Answer: 0.040 M/s
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