Question

Write neat please. Show step by step please. Read instructions carefully. Box in answer please. Thank you

Find the magnitude and direction of the magnetic field B,, for the protons to Calculate the magnitude and direction of the magnetic B2 for protons to move in (a) emerge from the slit with a velocity of 1 x 10 m/s. (b) a semicircle and arrive 9 cm to the right of the velocity selector. Calculate the total flux enclosed by the semicircular path in region B2 (c) h another singly charged ion comes out of the slit and arrives 11 cm to the right (d) of the velocity selector then what is its mass?

Answer 1

a) electric field between the playes, E = delta_V/x

= 10*10^3/0.02

= 5.0*10^5 N/C

for no deflection,

|Fb| = |Fe|

q*v*B*sin(90) = q*E

B = E/v

B1 = 5*10^5/(1*10^6)

= 0.50 T <<<<<<<<<<--------------------Answer

b) from the figure radius of the path, r = d/2

= (1 + 9)/2

= 5 cm

= 0.05 m

now use, r = m*v/(B2*q)

B2 = m*v/(r*q)

= 1.67*10^-27*1*10^6/(0.05*1.6*10^-19)

= 0.209 T <<<<<<<<----------------------Answer

c) flux through the semicircular path = (pi*r^2/2)*B2

= (pi*0.05^2/2)*0.209

= 8.21*10^-4 Weber (or) T.m^2 <<<<<<<<------------------Answer

d) r = (1 + 11)/2 = 6 cm = 0.06 m

now use, r = m*v/(B2*q)

m = B2*q*r/v

= 0.209*1.6*10^-19*0.06/(1*10^6)

= 2.01*10^-27 kg <<<<<<<<------------------Answer