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2.00 mol of helium is heated in a rigid container (constant volume). If 80.0 J are...

2.00 mol of helium is heated in a rigid container (constant volume). If 80.0 J are added to the container, what is the change in temperature of the gas?

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Answer #1

The change in temperature at constant volume is given by

AT nCy

where Q is the heat added, n is the number of moles, Cv is the heat capacity of Helium which is 12.5 J/K/mole

Therefore

AT- 80 3.21 K 2×12.5-321K

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