Question

7. Calculate the AHReaction for the reaction 2H2(g) + CO(g) → CH3OH() Using the following equations: CH3OH(1) + O2(g) → C(s) + 2H2O(1) C(s) + O2 (g) — CO(g) H2(g) + O2(g) → H2O(1) AH = -333.00 kJ AH =-111.52 kJ AH = -285.83 kJ

Answer 1

& we have to calculate Alako for : - 2494 colg) . chon(d) 0 using Ch₂ on (1) + 109) C(s) +240 (1) - AHYD = -333.0kJ /w/ (6) + Loz (9) Col) — 0 - Dhrung II =-111.52 kJ fola H₂(g) + Į 0₂ (9) 40(d) ® AH rm, IV = -285.83kJ /mnd I Now, from Hess how the enthalpy change for a reaction is the same whether it take place in one of several stages. Now , Adding eqn D d 8 msd me get I chon't I ₂ (9) C(s) + 240(d) c(s) + 40219) + Cou) + + + - C420H (1) + cest O₂(g) → eestzhot colo) I choncd) + O₂(g) → Caught 2 4₂0 Now, subtracting eq (2XIV) from ear meget CH2OH(l) + O₂ - Colg) +20o 2H2)+ O2(g) → 2H₂O (1) CH₂OH(d) Now, recursing ear so. Allons, I =-20 Houn, I Cola1 +24219) - we get ear Ost + Alor - (2x Dhrung)

ournal = -52-333)+ (-11:52)} - { 2x785831 →-|-333 - 171-52 + 571.66 7 - A Honen, I - 4 4 4.52 +571-66 - 127.14 kJ/mol