6)
Lets number the reaction as 0, 1, 2, 3 from top to bottom
required reaction should be written in terms of other reaction
This is Hess Law
required reaction can be written as:
reaction 0 = +1 * (reaction 1) +1 * (reaction 2) +1 * (reaction 3)
So, ΔHo rxn for required reaction will be:
ΔHo rxn = +1 * ΔHo rxn(reaction 1) +1 * ΔHo rxn(reaction 2) +1 * ΔHo rxn(reaction 3)
= +1 * (-202.0) +1 * (567.0) +1 * (22.6)
= 387.6 KJ
Answer: 387.6 KJ
Only 1 question at a time please
6. Calculate AH Reaction for the Reaction: N2H4 + 2N2O5 + 2HNO3 + 2NO2 + 2...
6. Calculate A HReaction for the Reaction: N2H4 + 2N2O5 = 2HNO3 + 2NO2 + 2 NH Using the following equations: H2 + 2N2 + 502-2HNO3 + 2NO2 N2H4 + 2NH + H2 2N205 2N2 + 502 AH = -202 kJ AH = +567 kJ AH = +22.6 kJ
7. Calculate the AHReaction for the reaction 2H2(g) + CO(g) → CH3OH() Using the following equations: CH3OH(1) + O2(g) → C(s) + 2H2O(1) C(s) + O2 (g) — CO(g) H2(g) + O2(g) → H2O(1) AH = -333.00 kJ AH =-111.52 kJ AH = -285.83 kJ
From the following equations, calculate AH for the reaction 2N2(g) + + 5O2(g) → 2N2O5(g) AH = ? H2(g) + O2(9) H206) AH = -285.8 kJ N2O5(g) + H200 2HNO30 AH = -76.6 kJ N2(g) + 302(g) + H219) - 2HNO30) AH = -348.2 kJ
show steps • What is the AH for the reaction: 2N2(g) + 502(9) -> 2N205 H2(g) + 12 Oz(9) -> H20(1) AH = -285.8 kJ N2O3(9) + H20 (1) -> 2HNO3 (1) AH = -76.6 kJ N2(g) + 302(g) + H2(g) -> 2HNO3 (1) AH = -348.2 kJ Click to add notes
Calculate AH for the following reaction, CaO(s) + CO2(g) CaCO3(s) given the thermochemical equations below. 2 Ca(s) + O2(g) + 2 Cao(s) AH = -1270.2 kJ C(s) + O2(g) CO2(g) AH = -393.5 kJ 2 Ca(s) + 2 C(s) + 3 O2(g) → 2 CaCO3(s) AH = -2413.8 kJ 0-750.1 kJ O +350.2 kJ 0 -178.3 kJ O +2870.6 kJ
(ii) Calculate AH° for the reaction N2H4(1) + O2(g) → N2(g) + 2H2O(1) using the data given below: 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(1) N2O(g) + 3H2(g) → N2H4(l) + H2O(1) 2NH3(g) + O2(g) → N2H4(1) + H2O(1) H2(g) + 1/2O2(g) → H2O(1) AH° = -1010. kJ AH° = -317 kJ AH° = -143 kJ AH° = -286 kJ
Calculate AH for the reaction N2H4(0) + O2(g) → N2(g) + 2 H2O(1) given the following data: Equation AH (kJ) 2 NH3(g) + 3 N2O(g) → 4 N2(g) + 3 H2O(l) -1010 N2O(g) + 3 H2(g) → N2H4(1) +H2O(1) -317 2 NH3(g) + 1202(g) → N2H4(1) + H20(1) -143 H2(g) + 1202(g) → H2O(H -286 AH=
reaction adi 2N219) + 50210) 2N2O5() AH = ? den aretle H2O AH = -285.8 kJ H2(g) + X0219) N, 05/9) + H20m 2HNO30) AH = -76.6 kJ N219) +302(0)+ H2(0) 2HNO30) AH = -348.2 kJ Don't add units in the answer! Yanit:
2) From the enthalpies of reaction provided, calculate the AH for the reaction of carbon with hydrogen as shown below. Is the reaction exothermic or endothermic? How many grams of C3Hg are produced with an enthalpy change of 209.4 kJ? 3 C(s) + 4 H2(g) - C He(a) moto-non (5+3=2 C3H8(9) + 5 O2(g) 3 CO2(g) + 4 H2O(9) AH = -2043 kJ/mol AH = -393.5 kJ/mol C(s) + Ozon 2 H2(g) + O2th CO2(g) 2 H20(9) AH = -483.6...
Calculate the standard reaction enthalpy for the reaction N2H4(ℓ) + H2(g) → 2 NH3(g) given N2H4(ℓ) + O2(g) → N2(g) + 2H2O(g) ∆H ◦ = −543 kJ · mol−1 2 H2(g) + O2(g) → 2 H2O(g) ∆H◦ = −484 kJ · mol−1 N2(g) + 3 H2(g) → 2 NH3(g) ∆H◦ = −92.2 kJ · mol−1 1.) −243 kJ · mol−1 2.) −59 kJ · mol−1 3.) −935 kJ · mol−1 4.) −151 kJ · mol−1 5.) −1119 kJ · mol−1