Sol :-
Given equations are :
H2 + 2 N2 + 5 O2 ----------> 2 HNO3 + 2 NO2 , ΔH1 = -202 KJ ................(1)
N2H4 ------------> 2 NH + H2 , ΔH2 = + 567 KJ .......................................(2)
2 N2O5 -----------> 2 N2 + 5 O2 , ΔH3 = + 22.6 KJ ...................................(3)
Aim equation is :
N2H4 + 2 N2O5 ----------------> 2 HNO3 + 2 NO2 + 2 NH , ΔH = ? ................................(4)
Aim equation can be obtain by adding equations (1), (2) and (3). Because enthalpy is an additive property of the system, therefore Change in enthalpy of a reaction (ΔH) of the aim equation will by the sum of ΔH1, ΔH2 and ΔH3.
So,
ΔH = ΔH1 + ΔH2 + ΔH3
ΔH = - 202 KJ + 567 KJ + 22.6 KJ
ΔH = + 387.6 KJ
Hence, Change in enthalpy of the reaction is = + 387.6 KJ
6. Calculate A HReaction for the Reaction: N2H4 + 2N2O5 = 2HNO3 + 2NO2 + 2 NH Using the following equations: H2 + 2...
6. Calculate AH Reaction for the Reaction: N2H4 + 2N2O5 + 2HNO3 + 2NO2 + 2 NH Using the following equations: H2 + 2N2 + 5022HNO3 + 2NO2 N2H4 + 2NH + H2 2N205 2N2 + 502 AH = -202 kJ AH = +567 kJ AH = +22.6 kJ 7. Calculate the AHReaction for the reaction 2H2(g) + CO(g) → CH3OH(1) Using the following equations: CH3OH() + O2(g) → C(s) + 2H2O() C(s) + 02 (9) — CO(g) H2(g) +...
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• What is the AH for the reaction: 2N2(g) + 502(9) -> 2N205 H2(g) + 12 Oz(9) -> H20(1) AH = -285.8 kJ N2O3(9) + H20 (1) -> 2HNO3 (1) AH = -76.6 kJ N2(g) + 302(g) + H2(g) -> 2HNO3 (1) AH = -348.2 kJ Click to add notes
From the following equations, calculate AH for the reaction 2N2(g) + + 5O2(g) → 2N2O5(g) AH = ? H2(g) + O2(9) H206) AH = -285.8 kJ N2O5(g) + H200 2HNO30 AH = -76.6 kJ N2(g) + 302(g) + H219) - 2HNO30) AH = -348.2 kJ
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Question 36 of 50 Submit Using the equations N2(g) + 3 H2(g) - 2 NH; (g) AH = -91.8 kJ/mol C(s) + 2 H (g) – CH2 (g) AH° = -74.9 kJ/mol H2 (g) + 2c(s) + N2 (g) - 2 HCN (g) AH = 270.3 kJ/mol Determine the enthalpy for the reaction CH, (g) + NH4 () – HCN (g) + 3 H2(g). kJ/mol 1 2 3 C +/- : 0 x 100
Using standard heats of formation, calculate the standard enthalpy change for the following reaction 2HBr(g) H2(g) + Br2() ANSWER kJ Submit Answer Retry Entire Group 2 more group attempts remaining Given the standard enthalpy changes for the following two reactions: (1) Zn(s)+ Cl2(g) ZnCl2(s) AH° = -415.0 kJ (2) Fe(s) + Cl2(g) FeCl2(s) AH° = -341.8 kJ what is the standard enthalpy change for the reaction: (3) Zn(s) + FeCl(s) AH° ? ZnCl2(s) + Fe(s) kJ Given the standard enthalpy...
(ii) Calculate AH° for the reaction N2H4(1) + O2(g) → N2(g) + 2H2O(1) using the data given below: 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(1) N2O(g) + 3H2(g) → N2H4(l) + H2O(1) 2NH3(g) + O2(g) → N2H4(1) + H2O(1) H2(g) + 1/2O2(g) → H2O(1) AH° = -1010. kJ AH° = -317 kJ AH° = -143 kJ AH° = -286 kJ
Calculate AH for the reaction N2H4(0) + O2(g) → N2(g) + 2 H2O(1) given the following data: Equation AH (kJ) 2 NH3(g) + 3 N2O(g) → 4 N2(g) + 3 H2O(l) -1010 N2O(g) + 3 H2(g) → N2H4(1) +H2O(1) -317 2 NH3(g) + 1202(g) → N2H4(1) + H20(1) -143 H2(g) + 1202(g) → H2O(H -286 AH=
Calculate the standard reaction enthalpy for the reaction N2H4(ℓ) + H2(g) → 2 NH3(g) given N2H4(ℓ) + O2(g) → N2(g) + 2H2O(g) ∆H ◦ = −543 kJ · mol−1 2 H2(g) + O2(g) → 2 H2O(g) ∆H◦ = −484 kJ · mol−1 N2(g) + 3 H2(g) → 2 NH3(g) ∆H◦ = −92.2 kJ · mol−1 1.) −243 kJ · mol−1 2.) −59 kJ · mol−1 3.) −935 kJ · mol−1 4.) −151 kJ · mol−1 5.) −1119 kJ · mol−1