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Thus, final reaction enthalpy is = +255.95 kj/mol
Question 36 of 50 Submit Using the equations N2(g) + 3 H2(g) - 2 NH; (g)...
Using the equations N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol C(s) + 2 H2 (g) → CH4 (g) AH° = -74.9 kJ/ mol H2 (g) + 2 C(s) + N2 (g) → 2 HCN (g) AH° = 270.3 kJ/mol Determine the enthalpy for the reaction CH4 (g) + NH3 (g) → HCN (g) + 3 H2 (g).
Dok Solutions Chex G tb ofibular syndesmosis articuli X study guide lab practical-Goog x + Question 3 of 20 Using the equations N2(g) + 3 H2(g) - 2 NH3 (9) AH = -91.8 kJ/mol C(s) + 2 H (g) – CHK (g) AH = -74.9 kJ/mol H (g) + 2 C(s) + N (g) + 2 HCN (g) AH = 270.3 kJ/mol Determine the enthalpy for the reaction CH4 (g) + NH3 (g) – HCN (g) + 3 H (g)....
What is the enthalpy of the following reaction: CH4(g) + NH3(g) à HCN(g) + 3H2(g) Use the data from the following three reactions: N2(g) + 3H2(g) à 2NH3(g) DrH° = -91.8 kJ C(s) + 2H2(g) à CH4(g) DrH° = -74.9 kJ H2(g) + 2C(s) + N2(g) à 2HCN(g) DrH° = +270.3 kJ 437 kJ 150 kJ 391 kJ 287 kJ 256 kJ
Given the following data for heats of reaction N2(g) + 3H2(g) ----> 2NH3(g) H = -91.8 kJ C(graphite) + 2H2(g) -------> CH4(g)H = -74.9kJ H2(g) + 2C(graphite) + N2(g) --------> 2HCN(g) H = 270.3 kJ Calculate H for the reaction used to make HCN CH4(g) + NH3(g) --------> HCN(g) + 3H2(g)
Experiment 13-Post-Lab Assignment 1. Athletes use cold packs containing ammonium nitrate solutions to ice their injuries. A 1.25 G sample of ammonium nitrate is dissolved in 25.0 mL of water to form a solution. The temperature of the solution falls from 25.8°C to 21.9°C. Find the enthalpy of the reaction (AH ), in kJ/mol. Assume the density of water is 1.00 g/mL and the heat capacity of the total solution to be 4.184 J/g °C 2. Calculate AHⓇ in kJ/mol...
Submit Question 33 of 50 For the chemical reaction H2 (g)+ F2 (g) 2 HF (g) AH = -79.2 kJ/mol. What is the enthalpy for the reaction 3 H2 (g)+3 F2 (g) 6 HF (g) kJ/mol 1 2 3 4 5 6 C 8 +- 0 x 100 O 7
Question 34 of 50 Submit Using the equations Si(S) + 2Cl2 (9) - SICI. (S) AH = -640.1 kJ/mol 2 Fe (s) + 3 Cl2 (g) - 2 FeCl (s) AH = -800.0 kJ/mol Determine the enthalpy for the reaction 3 SICIA (S) + 4 Fe (s) – 4 FeCl, (s) + 3 Si (S) kJ/mol 1 2 3 C +/- : 0 x 100 Question 34 of 50 Submit Using the equations Si(S) + 2Cl2 (9) - SICI. (S)...
Question 8 of 20 Using the equations H2(g) + F2 (g) → 2 HF (g) AH° = -79.2 kJ/mol C(s) + 2 F2 (g) → CF. (g) AH° = 141.3 kJ/mol 2 C(s) + 2 H2 (9) C2H4 (9) AH = -97.6 kJ/mol Determine the enthalpy for the reaction C2H4 (g) + 6 F2 (g) → 2 CF4 (9) + 4 HF (g). kJ/mol
Use the following equations N2 (g) + 3 H2 (g) 2 NH3 (g) N2 (g) + O2 (g) → 2 NO (g) 2 H2 (g) + O2 (g) + 2 H20 (1) DH = -99.22 kJ DH = + 180.5 kJ DH = - 571.6 kJ to calculate the enthalpy change for the reaction 4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H20 (1) DH = ?
Using the equations Ca (s)2 O (g) Сао (s) 2 H2 (g) Determine the enthalpy for the reaction Са (s) + 2 H0 () — Са(ОН)2 (s) + H2 (9). CaO (s) AH° = -635 kJ/mol -64 kJ/mol H2O ()Ca(OH)2 (s) AH O2 (g)2 H2O (I) AH° = -572 kJ/mol kJ/mol 1 2 3 4 6 C 5 7 8 9 +/- 0 x 100 LO 11.01 g of MgSO4 is placed into 100.0 mL of water. The water's temperature...