Submit Question 33 of 50 For the chemical reaction H2 (g)+ F2 (g) 2 HF (g)...
Question 8 of 20 Using the equations H2(g) + F2 (g) → 2 HF (g) AH° = -79.2 kJ/mol C(s) + 2 F2 (g) → CF. (g) AH° = 141.3 kJ/mol 2 C(s) + 2 H2 (9) C2H4 (9) AH = -97.6 kJ/mol Determine the enthalpy for the reaction C2H4 (g) + 6 F2 (g) → 2 CF4 (9) + 4 HF (g). kJ/mol
Question 36 of 50 Submit Using the equations N2(g) + 3 H2(g) - 2 NH; (g) AH = -91.8 kJ/mol C(s) + 2 H (g) – CH2 (g) AH° = -74.9 kJ/mol H2 (g) + 2c(s) + N2 (g) - 2 HCN (g) AH = 270.3 kJ/mol Determine the enthalpy for the reaction CH, (g) + NH4 () – HCN (g) + 3 H2(g). kJ/mol 1 2 3 C +/- : 0 x 100
for the chemical reaction H2(g) + F2(g) → 2HF(g); ∆H°=-79.2 kj/mol what is the enthalpy for the reaction 3H2+3F2->6HF
QUESTION 7 H2 and F2 react according to the following equation, forming HF. H2 + F2 --> 2HF (AH = -271 kJ/mol rxn) If H2(g) and F2(g) were reacted in a calorimeter, the reaction that occurred would be: O exothermic, and the water temperature in the calorimeter temperature would rise. O endothermic, and the water temperature in the calorimeter temperature would rise. endothermic, and the water temperature in the calorimeter temperature would fall. exothermic, and the water temperature in the...
Question 41 of 50 Submit Using the provided table, determine the enthalpy for the reaction 2 K(s)+2 H20() H2(g) 2 KOH (aq) AHi (kJ/mol) Substance K (s) 0 НаО () -285.8 КОН (ag) -482.4 kJ/mol 1 2 3 4 5 6 С 8 +- 0 x 100 O 7
Given that H2(g) + F2(g) → 2 HF(g) AH;xn = -546.6 kJ 2 H2(g) + O2(g) + 2H,0(1) AH;x= -571.6 kJ calculate the value of AHEX for 2F2(g) + 2 H20(1) + 4HF(g) + O2(8) AH
Please show all steps and work. ThanksTodd? < Time's Up! View Solution Using the equations H2 (g) + F2 (g) → 2 HF (g) AH° = -79.2 kJ/mol C(s) + 2 F2 (g) → CF4 (g) AH° = 141.3 kJ/mol Determine the enthalpy for the reaction C(s) + 4 HF (g) → CF, (g) + 2 H2 (g). | kJ/mol
6.65 From the enthalpies of reaction H2(8) + F2(8) 2 HF(8) AH = -537 kJ C(s) + 2 F2(8) CF4(8) AH = -680 kJ 2 C(s) + 2 H2(8) —— C2H4(8) AH = +52.3 kJ calculate AH for the reaction of ethylene with F2: C2H4(8) + 6 F2(8) — 2 CF4(8) + 4 HF(8)
Using the equations Ca (s)2 O (g) Сао (s) 2 H2 (g) Determine the enthalpy for the reaction Са (s) + 2 H0 () — Са(ОН)2 (s) + H2 (9). CaO (s) AH° = -635 kJ/mol -64 kJ/mol H2O ()Ca(OH)2 (s) AH O2 (g)2 H2O (I) AH° = -572 kJ/mol kJ/mol 1 2 3 4 6 C 5 7 8 9 +/- 0 x 100 LO 11.01 g of MgSO4 is placed into 100.0 mL of water. The water's temperature...
2. Calculate AH for the reaction of ethylene with F2. CHA(g) + 6 F2(g) → 2 CF.(g) + 4 HF(g) using the following enthalpies of reaction: 2 H2(g) + 2 F2(g) → 4 HF(g) AH, = -1074 kJ C(s) + 2 F2(g) → CF4(g) AH2 = -680 kJ C(s) + H2(g) → CH.(g) AH, = 26.2 kJ