Please show all steps and work. ThanksTodd?
Please show all steps and work. ThanksTodd? < Time's Up! View Solution Using the equations H2...
Question 8 of 20 Using the equations H2(g) + F2 (g) → 2 HF (g) AH° = -79.2 kJ/mol C(s) + 2 F2 (g) → CF. (g) AH° = 141.3 kJ/mol 2 C(s) + 2 H2 (9) C2H4 (9) AH = -97.6 kJ/mol Determine the enthalpy for the reaction C2H4 (g) + 6 F2 (g) → 2 CF4 (9) + 4 HF (g). kJ/mol
CHEMISTRY PLEASE HELP 1)Using the equations H₂ (g) + F₂ (g) → 2 HF (g) ∆H° = -79.2 kJ/mol C (s) + 2 F₂ (g) → CF₄ (g) ∆H° = 141.3 kJ/mol 2 C(s) + 2 H₂ (g) → C₂H₄ (g) ∆H° = -97.6 kJ/mol Determine the enthalpy for the reaction C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g). 2)Using the equations N₂ (g) + O₂ (g) → 2 NO (g) ∆H° = 180.6...
Submit Question 33 of 50 For the chemical reaction H2 (g)+ F2 (g) 2 HF (g) AH = -79.2 kJ/mol. What is the enthalpy for the reaction 3 H2 (g)+3 F2 (g) 6 HF (g) kJ/mol 1 2 3 4 5 6 C 8 +- 0 x 100 O 7
Calculate the standard enthalpy of formation of gaseous carbon tetrafluoride (CF4) using the following thermochemical information: Calculate the standard enthalpy of formation of gaseous carbon tetrafluoride (CF4) using the following thermochemical information: H2(g)F2(g) 2 HF(g) 2 CF4(g)4 HF(g) C2H4(g) +6 F2(g) C2H4(g)2 C(s) 2 H2(g) AH -537 kJ AH 2486.3 kJ AH -52.3 kJ ΔΗ - kJ
2. Calculate AH for the reaction of ethylene with F2. CHA(g) + 6 F2(g) → 2 CF.(g) + 4 HF(g) using the following enthalpies of reaction: 2 H2(g) + 2 F2(g) → 4 HF(g) AH, = -1074 kJ C(s) + 2 F2(g) → CF4(g) AH2 = -680 kJ C(s) + H2(g) → CH.(g) AH, = 26.2 kJ
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) + 6 F2 (g) → 2 CF4(g) + 4 HF (g) can be written as the sum of: C2H4 (9) ► 2 C(s) + 2 H2 (g) AH = -52.3 kJ/mol 2 C(s) + 4 F2 (9) ► 2 CF4(9) AH = -1360 kJ/mol 2 H2(g) + 2 F2 (g) → 4 HF (a) AH = -1074 kJ/mol C2H4(g) + 6 F2(g) → 2 CF4(g)...
Calculate the standard enthalpy of formation of gaseous carbon tetrafluoride (CF4) using the following thermochemical information: 2 HF(g) H2(g) + F2(g) H = +537 kJ 2 CF4(g) + 4 HF(g) C2H4(g) + 6 F2(g) H = +2486.3 kJ C2H4(g) 2 C(s) + 2 H2(g) H = -52.3 kJ Calculate the standard enthalpy of formation of gaseous carbon tetrafluoride (CF4) using the following thermochemical information: 2 HF(g) H2(g) + F2(g) H = +537 kJ 2 CF4(g) + 4 HF(g) C2H4(g) +...
Using the equations N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol C(s) + 2 H2 (g) → CH4 (g) AH° = -74.9 kJ/ mol H2 (g) + 2 C(s) + N2 (g) → 2 HCN (g) AH° = 270.3 kJ/mol Determine the enthalpy for the reaction CH4 (g) + NH3 (g) → HCN (g) + 3 H2 (g).
Please show all steps: Calculate the enthalpy for this reaction: Given the following thermochemical equations: c:H2(g) + (5/2)?2(g) > 2CO2(g) + H20(1) C(s) +02(g) -> CO2(g) ??? =-1299.5 kJ ??? -393.5 kJ ??? 285.8 kJ -> H2
6.65 From the enthalpies of reaction H2(8) + F2(8) 2 HF(8) AH = -537 kJ C(s) + 2 F2(8) CF4(8) AH = -680 kJ 2 C(s) + 2 H2(8) —— C2H4(8) AH = +52.3 kJ calculate AH for the reaction of ethylene with F2: C2H4(8) + 6 F2(8) — 2 CF4(8) + 4 HF(8)