Question

Using the equations N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol C(s) + 2 H2 (g) → CH4 (g) AH° = -74.9 kJ/ mol H2 (g) + 2

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Answer :- Page not Objective is to determine the enthalpy poor the coachion CHu(g) + NH3(g) → HON(8) + 3H2(g) Given equations+ page no NH3(9) AH → N219)+ H2(9) - 45.9 kJ/mol CHUC9) >.<(5) + 2 H2(g) = 70.9 kJ /mol HON (9) > H2(g) + C(s) +ì N2(9) --135

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