Question 36 of 50 Submit Using the equations N2(g) + 3 H2(g) - 2 NH; (g) AH = -91.8 kJ/mol C(s) + 2 H (g) – CH2 (g) AH° = -74.9 kJ/mol H2 (g) + 2c(s) + N2 (g) - 2 HCN (g) AH = 270.3 kJ/mol Determine the enthalpy for the reaction CH, (g) + NH4 () – HCN (g) + 3 H2(g). kJ/mol 1 2 3 C +/- : 0 x 100
Dok Solutions Chex G tb ofibular syndesmosis articuli X study guide lab practical-Goog x + Question 3 of 20 Using the equations N2(g) + 3 H2(g) - 2 NH3 (9) AH = -91.8 kJ/mol C(s) + 2 H (g) – CHK (g) AH = -74.9 kJ/mol H (g) + 2 C(s) + N (g) + 2 HCN (g) AH = 270.3 kJ/mol Determine the enthalpy for the reaction CH4 (g) + NH3 (g) – HCN (g) + 3 H (g)....
What is the enthalpy of the following reaction: CH4(g) + NH3(g) à HCN(g) + 3H2(g) Use the data from the following three reactions: N2(g) + 3H2(g) à 2NH3(g) DrH° = -91.8 kJ C(s) + 2H2(g) à CH4(g) DrH° = -74.9 kJ H2(g) + 2C(s) + N2(g) à 2HCN(g) DrH° = +270.3 kJ 437 kJ 150 kJ 391 kJ 287 kJ 256 kJ
Given the following data for heats of reaction N2(g) + 3H2(g) ----> 2NH3(g) H = -91.8 kJ C(graphite) + 2H2(g) -------> CH4(g)H = -74.9kJ H2(g) + 2C(graphite) + N2(g) --------> 2HCN(g) H = 270.3 kJ Calculate H for the reaction used to make HCN CH4(g) + NH3(g) --------> HCN(g) + 3H2(g)
Question 8 of 20 Using the equations H2(g) + F2 (g) → 2 HF (g) AH° = -79.2 kJ/mol C(s) + 2 F2 (g) → CF. (g) AH° = 141.3 kJ/mol 2 C(s) + 2 H2 (9) C2H4 (9) AH = -97.6 kJ/mol Determine the enthalpy for the reaction C2H4 (g) + 6 F2 (g) → 2 CF4 (9) + 4 HF (g). kJ/mol
Use the following equations N2 (g) + 3 H2 (g) 2 NH3 (g) N2 (g) + O2 (g) → 2 NO (g) 2 H2 (g) + O2 (g) + 2 H20 (1) DH = -99.22 kJ DH = + 180.5 kJ DH = - 571.6 kJ to calculate the enthalpy change for the reaction 4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H20 (1) DH = ?
Self-test 3.5 Determine the difference AH-AU for the reaction N2(g) + 3 H2(g) → 2 NH3(g) at 500 °C. Answer:-13 kJ mol-1
Experiment 13-Post-Lab Assignment 1. Athletes use cold packs containing ammonium nitrate solutions to ice their injuries. A 1.25 G sample of ammonium nitrate is dissolved in 25.0 mL of water to form a solution. The temperature of the solution falls from 25.8°C to 21.9°C. Find the enthalpy of the reaction (AH ), in kJ/mol. Assume the density of water is 1.00 g/mL and the heat capacity of the total solution to be 4.184 J/g °C 2. Calculate AHⓇ in kJ/mol...
Hydrogen reacts with nitrogen to form ammonia (NH3) according to the reaction 3 H2(g) + N2(g) → 2 NH3(g). The value of AH is -92.38 kJ/mol, and that of AS is -198.2 J/mol · K. Determine AG at 50.00°C for the preparation of 2 moles of NH3. (answer in kJ/mol) Answer: -56.723 Check
3) N2(g) + 3 H2(g) → 2 NH3(g) AH = - 46.1kJ A) For the above reaction what is the sign of ASsys? (Is entropy of the reaction increasing or decreasing?) B) Calculate the value of Assurr using the information given at 25°C