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for the chemical reaction H2(g) + F2(g) → 2HF(g); ∆H°=-79.2 kj/mol what is the enthalpy for...

for the chemical reaction H2(g) + F2(g) → 2HF(g); ∆H°=-79.2 kj/mol what is the enthalpy for the reaction 3H2+3F2->6HF

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(6 (6) Given H₂ +62 2 Hfcg, AH = 79.2 - if we multiply reaction by 341209+ 36210). — 6HFLG*3) ie, -79,2*3 =-237.6. Axº = -237

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