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How many grams of solid potassium fluoride should be added to 0.500 L of a 0.159 M hydrofluoric acid solution to prepare a bu
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. Lets ng of kf should be added Now, molar mats of KF = 58.0967 gmolat So, xg of KF= x 8 at = 58:0957 fondin - 5800927 mod of

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