1. (a) Force F = -21 - 4 (N) is applied to a metal bar in the x-y plane with one end of the bar at the origin. The point on the bar of application of the force is (x - 2m, y m). Use the position vector (1) of the point of action of the force to find the magnitude and direction of the torque. Hint: Employ method of determinant to find cross product (6pts) Show working (2pts) Magnitude...
A metal bar is in the xy-plane with one end of the bar at the origin. A force F =( 6.39 N )i +( -3.16 N )j is applied to the bar at the point x = 2.29 m, y = 3.19 m.A) What is the position vector r⃗ for the point where the force is applied?Enter the x and y components of the radius vector separated by a comma.*B) What is the magnitude of the torque with respect to...
A metal bar is in the xy-plane with one end of the bar at the origin. A force F =(6.12 N )i+(-3.27 N )j is applied to the bar at the point x = 2.07 m, y = 3.02 m. Part A What is the position vector for the point where the force is applied?Part B What is the magnitude of the torque with respect to the origin produced by F?