2,40 Particle 1 is subjected to an acceleration a=-ku, particle 2 is subjected to akt, and...

Question

Question

Answer 1

Answer #1

Particle 2

a = -kt

dv/dt = -kt

v = -kt^2/2 + Vo

V = -0.1t^2/2 + 10

Image result for v t graph for decreasing acceleration

particle 1

a = -kv

dv/dt = -kv

dv/v = -kt

logv = -kt + logVo

log(V/Vo) = -kt

V = Voe^(-kt)

= 10e^(-0.1t)

2.5 2.0 1.5 1.0 0.5 0 2 3

Answer 2

Similar Homework Help Questions

The acceleration of a particle is a constant. At t = 0 the velocity of the...

The acceleration of a particle is a constant. At t = 0 the velocity of the particle is (14.0↑ + 14.9 your answers.) m/s. At t = 5.1 s te velocity is 1 1.4j m/s. (Use the following as necessary: t. Do not include units in (a) What is the particle's acceleration (in m/s)? a = | |- 2.75 | 1+1-0.69 j (b) How do the position (in m) and velocity (in m/s) vary with time? Assume the particle is...
A particle of mass m is constrained to move along the x-axis and is subjected to...

A particle of mass m is constrained to move along the x-axis and is subjected to a force given by . Assuming the particle had an initial velocity of Vo and was at the origin at t = 0, find an equation for the particle's velocity and set up the integral from which the position equation as a function of time could be determined. NOTE: You do not need to evaluate the integral for the position as a function of...
12-17. and t 0. If it is subjected to a deceleration of a--k where k is...

12-17. and t 0. If it is subjected to a deceleration of a--k where k is a constant, determine its velocity and position as functions of time. A particle is moving with a velocity of vo when s 0

A particle moves in a straight line with the acceleration shown. The particle starts from the...

A particle moves in a straight line with the acceleration shown. The particle starts from the origin with V.=-2 m/s. Construct a) Velocity versus time and Position versus time curves for 0 <t< 18 seconds b) Determine the position and the velocity of the particle when t=18 seconds c) Determine the total distance traveled. ooo a( )
1) 2D kinematics (rectangular coordinates) - A particle moving in the x-y plane has an acceleration...

1) 2D kinematics (rectangular coordinates) - A particle moving in the x-y plane has an acceleration in the y-direction given as ay -3t ft/s2 and an x-position ofx 3t + 2 ft. When t0, yo3ft and Vo, -4ft/s. a) Derive expressions for x, vx, ax, V, Vy, ay as functions of time. b) At times t 0,1,2 seconds, calculate the magnitude of velocity and the angle it makes with the x-axis. c) At times t 0,1,2 seconds, calculate the magnitude...
PH 221 In Class Work 1. A particle falls with the acceleration due to gravity which...

PH 221 In Class Work 1. A particle falls with the acceleration due to gravity which has magnitude 9.8 m's At time , 0 the particle is released from rest (i.c., initial velocity ve0) at a height of 100 m from the ground. a.Make a sketch representing the initial conditions of the problem showing: i. The origin and direction of the y-axis. ii. The position of the particle at , 0. iii. The velocity of the particle at to-0. iv....

12-15. A particle is moving with a velocity of vo when s-0 and t 0. If...

12-15. A particle is moving with a velocity of vo when s-0 and t 0. If it is subjected to a deceleration of a-kv3, where k is a constant, determine its velocity and position as functions of time,
A particle starts from rest at the origin with an acceleration vector that has magnitude 6...

A particle starts from rest at the origin with an acceleration vector that has magnitude 6 m/s2 and direction 29 ∘ above the positive x axis. What is the vx component of its velocity vector 25 s later? What is the vy component of its velocity vector 25 s s later? What is the particle’s dx position at that time? What is the particle’s dy position at that time?
the acceleration of a particle as it moves along a straight line is given by a=(2t-1)m/s^2, where t is in seconds

the acceleration of a particle as it moves along a straight line is given by a=(2t-1)m/s^2, where t is in seconds.if s=1m and v= 2m/s when t=0,determine the particles velocity and position when t=6s. Also, determine the total distance the particle travels during this time period.

2) The magnitude of the acceleration of an object moving in rectilinear motion is a=12 sn,...

2) The magnitude of the acceleration of an object moving in rectilinear motion is a=12 sn, where a is in m/s' and s is the distance of the point from the origin in meters. When the time t is 2 seconds, the point is 16m to the right of the origin and has a velocity of 32m/s to the right and an acceleration of 48m/s to the right. Determine: a) the velocity and acceleration of the particle when time is...