The acceleration of a particle is a constant. At t = 0 the velocity of the...
At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of vector v i = (3.00 i - 2.00 j) m/s and is at the origin. At t = 3.60 s, the particle's velocity is vector v = (8.90 i + 7.70 j) m/s. (Use the following as necessary: t. Round your coefficients to two decimal places.) (a) Find the acceleration of the particle at any time t. vector a = m/s2 (b)...
At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of vector v i = (3.00 i - 2.00 j) m/s and is at the origin. At t = 3.70 s, the particle's velocity is vector v = (7.40 i + 6.90 j) m/s. (Use the following as necessary: t. Round your coefficients to two decimal places.) (a) Find the acceleration of the particle at any time t. vector a = m/s2 (b)...
A particle leaves the origin with an initial velocity v⃗ =(2.40m/s)x^, and moves with constant acceleration a⃗ =(−1.90m/s2)x^+(3.20m/s2)y^. How far does the particle move in the x direction before turning around? What is the particle's velocity at this time? Calculate the particle's position at t = 0.500 s, 1.00 s, 1.50 s, and 2.00 s. Use these results to sketch x and y positions versus time for the particle.
A particle starts from the origin at t = 0 with an initial velocity of 5.5 m/s along the positive x axis.If the acceleration is (-2.9 i^ + 4.7 j^)m/s2, determine (a)the velocity and (b)position of the particle at the moment it reaches its maximum x coordinate
gives the acceleration a versus time t for a particle moving along an x axis. The a-axis scale is set by as = 14.0 m/s2. At t = -2.0 s, the particle's velocity is10.0 m/s. What is its velocity at t = 6.0 s?
The vector position of a particle varies in time according to the expression r = 8.20 i-5.60p j where r is in meters and t is in seconds. (a) Find an expression for the velocity of the particle as a function of time. (Use any variable or symbol stated above as necessary.) x m/s Determine the acceleration of the particle as a function of time. (Use any variable or symbol stated above as necessary.) X m/s2 (c) Calculate the particle's...
A particle initially located at the origin has an initial velocity of vi = 30.0 î m/s + 50.0 ĵ m/s. If the velocity of the particle at t = 5.0 s is v = 12.0 î m/s + 60.0 ĵ m/s, what is the particle's acceleration (in m/s2)? (Express your answer in vector form.)
1.The "kinematic equations" are used to solve problems when there is a particle with constant acceleration. increasing acceleration. variable acceleration. decreasing acceleration. 2. A Honda Civic initially starts from rest, then accelerates at a rate of 3 m/s2 for 10 s. What is its final velocity? 30 m 30 m/s 3 m/s 0.3 m/s 3. magnitude of this acceleration is approximately 9.80 m/s2, and is known as the acceleration due to gravity. We use the following symbol to indicate this...
the velocity of a particle is given by v=[16t^2i+4t^3j +(5t+2)k]m/s, where t is in seconds. If the particle is at the origin when t=0, determine the magnitude of the particle's acceleration when t=2s. What is the x,y,z coordinate position of the particle at this instant.
find the velocity The figure below gives the acceleration a versus time t for a particle moving along an x axis. At t--2.0 s, the particle's velocity is-35 m/s, what is its velocity at t = 6.0 s? m/s a (m/s2) t (s)