the velocity of a particle is given by v=[16t^2i+4t^3j +(5t+2)k]m/s, where t is in seconds
The velocity ofa particle is defined by v (-2i+(3-20A, m/s where t is in seconds. If r 0 when t 0, determine the displacement of the particle during the time interval t As (-8/-4A, m As (-6i+-6A. m As (-10/-2A.m As-(-4, m 1 s and t 4 s. A motor gives a disk A an angular acceleration of aA (2t+3) rads, where t is in seconds. If the inidal angular velocity of the disk is Dg 5 rads, determine the...
dynamics Problem 2. (a) If the position of a particle is given by x = 16t – 5t4, where x is in meters and t is in seconds, when if ever is the particle's velocity zero? (b) When is its acceleration a zero?
3. The particle travels along a straight line with a velocity (22 - 5t) m/s, where t is in seconds. If s 10 m whent0, determine the following: a. The position of the particle when t-4s b. The total distance traveled during the time interval from t-0 to 4 s c. The acceleration when t 2s
A particle's velocity is given by v(t) = 21 + cos(5t). Find the following. (3 pts. each) A) The position function for the particle if its position is 5 when t = 0. B) The acceleration of the particle at I =*
the position of a particle moving along an x axis is given by x= 15t^2-5t^3, where x is in meters and t is in seconds. Determine a) the position ,b) the velocity,and c) the acceleration of the particle at t= 7.00s d) what is the maximum positive coordinate reached by the particle
Given s(t) = 2+ + 4t, where s(t) is in feet and t is in seconds, find each of the following. a) v(t) b) aſt) c) The velocity and acceleration when t= 2 sec a) v(t) = b) a(t) = c) When t = 2 sec, the velocity is (Simplify your answer.) When t = 2 sec, the acceleration is (Simplify your answer.)
If the position of a particle is given by x=20t-5t^3 x = 20 t ? 5 t 3 , with x in meters and t in seconds, when, if ever, is the particle's velocity zero? b) When is the acceleration a zero? c) For what time range (positive or negative) is a negative? d) Positive? e) Graph x ( t ) , v ( t ) , and a ( t ) .
The velocity of a particle traveling in a straight line is given by v (6t-3t2) m/s, where t is in seconds. Suppose that s 0 when t0. a. Determine the particle's deceleration when t3.6s b. Determine the particle's position when t 3.6 s C. How far has the particle traveled during the 3.6-s time interval? d. What is the average speed of the particle for the time period given in previous part?
v=(4 + + 2) m/s 1. The particle is moving with a velocity of v = (4 + 2) m/s, where t is in seconds. When t = 1 s, determine: (1) the magnitude of velocity, (2) the magnitude of acceleration, and (3) the position of the particle. (15 points) va (4+²+2) t= ls racom 6 m
Mathematics 1E SESSION 1, 2018 A particle undergoing straight line motion has velocity (in ms 9. given by [10 Marks] v(t) = e2 -3e at time t seconds, where t > 0. a) Determine the initial velocity b) Show that the particle is stationary when t In 3 c) Determine an expression for a(t), the acceleration of the particle. d) Given that v(In 2)= -2 and a(ln 2) 2, determine whether the particle's speed is increasing or decreasing when t=...