At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of vector v i = (3.00 i - 2.00 j) m/s and is at the origin. At t = 3.60 s, the particle's velocity is vector v = (8.90 i + 7.70 j) m/s. (Use the following as necessary: t. Round your coefficients to two decimal places.) (a) Find the acceleration of the particle at any time t. vector a = m/s2 (b) Find its coordinates at any time t. x = m y = m
At t = 0, a particle moving in the xy plane with constant acceleration has a...
At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of vector v i = (3.00 i - 2.00 j) m/s and is at the origin. At t = 3.70 s, the particle's velocity is vector v = (7.40 i + 6.90 j) m/s. (Use the following as necessary: t. Round your coefficients to two decimal places.) (a) Find the acceleration of the particle at any time t. vector a = m/s2 (b)...
A particle initially located at the origin has an acceleration of vector a = 2.00ĵ m/s2 and an initial velocity of vector v i = 6.00î m/s. (a) Find the vector position of the particle at any time t (where t is measured in seconds). ( t î + t2 ĵ) m (b) Find the velocity of the particle at any time t. ( î + t ĵ) m/s (c) Find the coordinates of the particle at t = 3.00...
A particle moves in the xy plane with constant acceleration. At time t=0 s, the position vector for the particle is r=9.70mx^+4.30my^. The acceleration is given by the vector a=8.00m/s^2x^+3.90m/s^2y^. The velocity vector at time t=o s is v=2.80m/sx^ - 7.00m/sy^. What is the magnitude of the position vector at time t= 2.10 s? What is the angle between the position vector and the positive x-axis at time t= 2.10 s?
A particle initially located at the origin has an acceleration of vector a = 4.00ĵ m/s2 and an initial velocity of vector v i = 9.00î m/s. (a) Find the vector position of the particle at any time t (where t is measured in seconds). ( t î + t2 ĵ) m (b) Find the velocity of the particle at any time t. ( î + t ĵ) m/s (c) Find the coordinates of the particle at t = 9.00...
The acceleration of a particle is a constant. At t = 0 the velocity of the particle is (14.0↑ + 14.9 your answers.) m/s. At t = 5.1 s te velocity is 1 1.4j m/s. (Use the following as necessary: t. Do not include units in (a) What is the particle's acceleration (in m/s)? a = | |- 2.75 | 1+1-0.69 j (b) How do the position (in m) and velocity (in m/s) vary with time? Assume the particle is...
please i need help asap Problem 1 The acceleration of a particle moving only on a horizontal xy plane is given by a=3ti+4tj, where a is in meters per seconds squared and t is in seconds, at t=0, the position vector r=(20.0m)i+(40.0m)j locates the particles, which then has the velocity vector v=(5.00m/s)i+(2.00m's)j. at t=4.00s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis?...
The position T of a particle moving in an xy plane is given by (3.006.00(3.00 1.00r with in meters and t in seconds. In unit-vector notation, calculate (a) r, (b) v, and (c) a fort 3.00 s. (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t- 3.00 s? Give your answer in the range of (-180°; 180°) (a) Number (b) Number (c) Number (d) Number j...
The position r of a particle moving in an xy plane is given by r = (4.00t^3 - 4.00t) i + (4.00 - 1.00t^4) j with r in meters and t in seconds. In unit-vector notation, calculate (a) r, (b) V, and (c) a for t = 2.00 s, (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t = 2.00 s? Give your answer in the...
4. -14 points SerPSE9 4.P006.W A particle initially located at the origin has an acceleration of a 1.00j m/s2 and an initial velocity of V, 8.001 m/s. (a) Find the vector position of the particle at any time t (where t is measured in seconds). t2 1) m tl+ (b) Find the velocity of the particle at any time t. t 1) m/s (c) Find the coordinates of the particle at t 5.00 s. (d) Find the speed of the...
The vector position of a particle varies in time according to the expression r = 8.20 i-5.60p j where r is in meters and t is in seconds. (a) Find an expression for the velocity of the particle as a function of time. (Use any variable or symbol stated above as necessary.) x m/s Determine the acceleration of the particle as a function of time. (Use any variable or symbol stated above as necessary.) X m/s2 (c) Calculate the particle's...