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72 Laboratory 6 Organic Functional Group Tests 9. Complete the following equations: a. CH,COOH + H,0...
Calculate the standard free-energy change and the equilibrium constant Kc for the following reaction at 25°C....
Calculate the standard free-energy change and the equilibrium constant Kc for the following reaction at 25°C. See Appendix C for data. Fe(s) + Cu2+ (aq) = Fe2+ (aq) + Cu(s) Find equilibrium constan + K at 25°C Appendix C Thermodynamic Quantities for Substances and Ions at 25°C Substance or lon AH; (kJ/mol) AG; (kJ/mol (J/mol-K) 20.87 Substance or lon Ba(OH),(s) ΔΗ: (kJ/mol) -946.3 --3342.2 AG (kJ/mol) -859.3 -2793 (J/mol K) 107.1 427 Ba(OH), 8H,O(s) BaSO (8) - 1473.2 -1362.3 132.2...
Using enthalpies of formation (Appendix C), calculate ΔH ° for the following reaction at 25°C. Also...
Using enthalpies of formation
(Appendix C), calculate ΔH ° for the following reaction at 25°C.
Also calculate ΔS ° for this reaction from standard entropies at
25°C. Use these values to calculate ΔG ° for the reaction at this
temperature. COCl2(g) + H2O(l ) h CO2(g) + 2HCl(g).
Appendix C Thermodynamic Quantities for Substances and Ions at 25°C Substance or lon AH; (kW/mol) 0 AG: (kJ/mol) 0 S° (J/mol-K) 20.87 ΔΗ, (kJ/mol) -946.3 - 33422 AG; {kj/mol) --859,3 -2793 (J/mol-K)...
4. Only ideal processes can be thermodynamically "reversible." Why can rear proce y can real process...
4. Only ideal processes can be thermodynamically "reversible." Why can rear proce y can real processes not be? 5. Consider the following reactions. (Note: if this were an exam we would give you an excerpt on tabular data from Appendix 4 (Table A4.3). 2Fe(s) + 3Cla(s) 2FeCl(s) N2H4(8) + H2(g) + 2NH3(g) (a) Would you expect the entropy change for the above reaction to be >0, <0, or no (small)? Justify your answer. (d) Would you expect the entropy change...
Calculate the standard free-energy change and the equilibrium constant Kc for the following reaction at 25°C. See Appendix C for data. Fe(s) + Cu2+ (aq) = Fe2+ (aq) + Cu(s) Find equilibrium constan + K at 25°C Appendix C Thermodynamic Quantities for Substances and Ions at 25°C Substance or lon AH; (kJ/mol) AG; (kJ/mol (J/mol-K) 20.87 Substance or lon Ba(OH),(s) ΔΗ: (kJ/mol) -946.3 --3342.2 AG (kJ/mol) -859.3 -2793 (J/mol K) 107.1 427 Ba(OH), 8H,O(s) BaSO (8) - 1473.2 -1362.3 132.2...
Using enthalpies of formation
(Appendix C), calculate ΔH ° for the following reaction at 25°C.
Also calculate ΔS ° for this reaction from standard entropies at
25°C. Use these values to calculate ΔG ° for the reaction at this
temperature. COCl2(g) + H2O(l ) h CO2(g) + 2HCl(g).
Appendix C Thermodynamic Quantities for Substances and Ions at 25°C Substance or lon AH; (kW/mol) 0 AG: (kJ/mol) 0 S° (J/mol-K) 20.87 ΔΗ, (kJ/mol) -946.3 - 33422 AG; {kj/mol) --859,3 -2793 (J/mol-K)...
4. Only ideal processes can be thermodynamically "reversible." Why can rear proce y can real processes not be? 5. Consider the following reactions. (Note: if this were an exam we would give you an excerpt on tabular data from Appendix 4 (Table A4.3). 2Fe(s) + 3Cla(s) 2FeCl(s) N2H4(8) + H2(g) + 2NH3(g) (a) Would you expect the entropy change for the above reaction to be >0, <0, or no (small)? Justify your answer. (d) Would you expect the entropy change...
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