Question

The pH of a 0.053 M weak monoprotic acid is 3.05. Calculate the K, of the acid. K= 10 Enter your answer in scientific notatio
The base ionization constant of ammonia is 1.8 x 10 . In a 0.070 M NH3 solution, what percentage of the NH3 is present as NH
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Q1. Ka = 1.52 x 10-5

Q2. percentage = 1.59 %

Explanation

Q1. pH = 3.05

[H+] = 10-pH

[H+] = 10-3.05

[H+] = 8.9 x 10-4 M

Ka = [H+]2 / (C - [H+])

where C = initial concentration of acid = 0.053 M

Ka = (8.9 x 10-4 M)2 / (0.053 M - 8.9 x 10-4 M)

Ka = 1.52 x 10-5

Add a comment
Know the answer?
Add Answer to:
The pH of a 0.053 M weak monoprotic acid is 3.05. Calculate the K, of the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT