Question

28. Analysis of nicotine gave 74.0% C, 8.7% H, and 17.3% N, by mass. Its molar mass was determined to be 162 g/mol. What is t

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Ginen, Carbon contrent - 74.1. Hydrogen content = 8.7l. nitrogen content = 12.84. Molecular mass - 162g 1mol Element of compo

Add a comment
Know the answer?
Add Answer to:
28. Analysis of nicotine gave 74.0% C, 8.7% H, and 17.3% N, by mass. Its molar...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 00 t, 00 #14 Homework Worksheet Empirical and Molecular Formula 1. Nicotine is a poisonous compound...

    00 t, 00 #14 Homework Worksheet Empirical and Molecular Formula 1. Nicotine is a poisonous compound found in tobacco leaves. Analysis of nicotine shows that it contains 74.0% C, 8.65% Hand 17.35% N. a. What is the empirical formula for nicotine? US MolsN mol 01 m 174,07- b. If the molecular weight of nicotine is 162 g/mol, what is the molecular formula for nicotine? 2. Mandelic acid is an organic acid with the following percent compostions: 63.15% C, 5.30% H...

  • 6. A certain compound has the following elemental composition: C, H, O, N. In a combustion...

    6. A certain compound has the following elemental composition: C, H, O, N. In a combustion analysis, 3.895 g of it was combusted to produce 9.087 g of CO2 and 3.411 g H20. Separate analysis determined that it is 12.38% N, and its molar mass is 226.4 g/mol. Determine its empirical and molecular formula. 6. A certain compound has the following elemental composition: C, H, O, N. In a combustion analysis, 3.895 g of it was combusted to produce 9.087...

  • An analysis of nicotine, a poisonous compound found in tobacco leaves, shows that it is 74.03%...

    An analysis of nicotine, a poisonous compound found in tobacco leaves, shows that it is 74.03% Carbon, 8.70% Hydrogen, and 17.27% Nitrogen. Its molar mass is 162 grams/mole. What are the empirical and molecular formulas of nicotine?

  • 5. 74.1% carbon, 8.6% hydrogen, & 17.3% nitrogen by mass. Its molar mass = 160 g/mol....

    5. 74.1% carbon, 8.6% hydrogen, & 17.3% nitrogen by mass. Its molar mass = 160 g/mol. 6. 59.0% carbon, 7.1% hydrogen, 26.2%oxygen, & 7.7% nitrogen by mass. Its molar mass = 180 g/mol. Find the molecular formula of a compound given: 7. 212.1 g sample with 42.4 g hydrogen and 169.7 g carbon. Molar mass = 30.0 g/mol 8. Carbon & Hydrogen containing compound sample with molar mass = 114.26 g/mol. 1 mole of the sample contains 18.17 g hydrogen....

  • An herbicide contains only C , H , Cl , and N . The complete combustion...

    An herbicide contains only C , H , Cl , and N . The complete combustion of a 125.0 mg sample of the herbicide in excess oxygen produced 130.7 mL of CO2 and 76.26 mL of H2O vapor at STP. A separate analysis determined the 125.0 mg sample contained 34.46 mg Cl . Determine the percent composition of the herbicide. percent carbon: % percent hydrogen: % percent chlorine: % percent nitrogen: % Determine the empirical formula of the herbicide. empirical...

  • onent of protein called threonine has an approximate molar mass of 120 g/mole. If the percent...

    onent of protein called threonine has an approximate molar mass of 120 g/mole. If the percent sition is as follows, find the empirical and molecular formulas of threonine? C = 40.33%, H = 7.616%, O = 40.29% and N = 11.76% aethyllead, the "lead" additive in leaded gasoline, has a percent composition by mass of 64.06% Pb, 29.71 % C and 6.23% H. What is the empirical formula of tetraethyllead? A 50.51 g sample of a compound made from iron...

  • If the substance has a molecular mass of 160 +/- 5 g/mol, what is its molecular formula?

    (a) The characteristic odor of pineapple is due to ethyl butyrate, a compound containing carbon, hydrogen, and oxygen. Combustion of 7.23 mg of ethyl butyrate produces16.43 mg of CO2 and 6.71 mg of H2O. What is the empirical formula of the compound? (Type your answer using the format CO2 for CO2.)(b) Nicotine, a component of tobacco, is composed of C, H, and N. A 4.725 mg sample of nicotine was combusted, producing 12.818 mg of CO2 and 3.675 mg of...

  • The empirical formula of a compound is known to be CH2, and its molar mass is...

    The empirical formula of a compound is known to be CH2, and its molar mass is 56 g/mol. What is the molecular formula of the compound? C3H20 C4H8 O C₂H4 CH2 O C₃H6

  • The complete combustion of 81.0 mg of a compound containing C,H, and O, and extracted from...

    The complete combustion of 81.0 mg of a compound containing C,H, and O, and extracted from the bark of a sassafras tree, produces 220.0 mg of CO2 and 45.0 mg of H20. What is the empirical formula? What is the molecular formula if the molar mass of the compound is 162 g/mol?

  • ​An organic compound has the empirical formula C₂H₄NO.

    An organic compound has the empirical formula C₂H₄NO. If its molar mass is 116.1 g/mol, what is the molecular formula of the compound?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT