An analysis of nicotine, a poisonous compound found in tobacco leaves, shows that it is 74.03% Carbon, 8.70% Hydrogen, and 17.27% Nitrogen. Its molar mass is 162 grams/mole. What are the empirical and molecular formulas of nicotine?
An analysis of nicotine, a poisonous compound found in tobacco leaves, shows that it is 74.03%...
00 t, 00 #14 Homework Worksheet Empirical and Molecular Formula 1. Nicotine is a poisonous compound found in tobacco leaves. Analysis of nicotine shows that it contains 74.0% C, 8.65% Hand 17.35% N. a. What is the empirical formula for nicotine? US MolsN mol 01 m 174,07- b. If the molecular weight of nicotine is 162 g/mol, what is the molecular formula for nicotine? 2. Mandelic acid is an organic acid with the following percent compostions: 63.15% C, 5.30% H...
5. Nicotine, an alkaloid that is mainly responsible for the addictive nature of cigarettes, contains 74.02% C, 8.710% H, and 17.27% N. Its molecular mass was found to be 162.28 g/mol. What is the empirical and molecular formulas of this compound? Show all your calculations
compound is found to contain 63.65 % nitrogen and 36.35 % oxygen by mass. the empirical formula is? the molar mass is 44.02 g/mol. what is the molecular formula? A compound is found to contain 6.360 % silicon , 36.18 % bromine , and 57.46 % iodine by mass. the empirical formula is? the molar mass is 441.7. what is the molecular formula? A compound is found to contain 64.80 % carbon , 13.62 % hydrogen , and 21.58 %...
3. Acrylic acid, used in the manufacture of some plastics, has the composition 50.0% C, 5.6% H, and 44.4% O by mass. What is the empirical formula? 4. Urea contains C, H, N, and O. A 2.54 gram sample of urea is found to contain 0.51 g carbon, 0.17 g of hydrogen, and 1.19 g of nitrogen. What is the empirical formula of urea? 5. Putrescine, a substance produced by decaying animals, is composed of 54.5 % carbon, 13.6% hydrogen,...
28. Analysis of nicotine gave 74.0% C, 8.7% H, and 17.3% N, by mass. Its molar mass was determined to be 162 g/mol. What is the empirical formula and the molecular formula of nicotine?!
7 A compound having an approximate molar mass of 165-170g has the following percentage composition by mass: carbon, 42.87%; hydrogen, 3.598%, oxygen, 28.55%, nitrogen 25.00%. Determine the empirical and molecular formulas of the compound. A compound consists of carbon and hydrogen. The molar mass of this compound id 44.1 g/mol The percent by mass of carbon is 81.71%. Determine the empirical and molecular formulas of the compound 8.
The qualitative analysis of an organic compound showed C, H, O in combustion analysis of 0.20 34 g of a compound gave 0.5 911 g of CO2 and 0.10 36 g of H2O. the molecular weight of the compound was determined by the freezing point pressure method and was found in 210 from the above experimental results. determine the molecular formula of the compound 2. A compound is shown by qualitative analysis to contain carbon nitrogen oxygen and hydrogen combustion...
20) A compound was analyzed and found to be 47% Carbon, 11% Hydrogen and 42% Oxygen, What is its Empirical Formula? What is its molecular formula if its molecular weight is 304 g/mole?
20) A compound was analyzed and found to be 47% Carbon, 11% Hydrogen and 42% Oxygen, What is its Empirical Formula? What is its molecular formula if its molecular weight is 304 g/mole?
d. 2.1130 grams of an unknown organic compound was found to occupy 305 mL at 757 torr and 100°C. i. Find its approximate molar mass using the same approach as you did for today's experiment. ii. It is found on analysis to consist of 49.3% C, 12.3% H, and the rest is nitrogen. Find its empirical formula. iii.. Using the results of parti and ii, determine the true molecular formula and the true molar mass for the unknown substance. Show...