compound is found to contain 63.65 % nitrogen and 36.35 % oxygen by mass. the empirical formula is? the molar mass is 44.02 g/mol. what is the molecular formula?
A compound is found to contain 6.360 % silicon , 36.18 % bromine , and 57.46 % iodine by mass. the empirical formula is? the molar mass is 441.7. what is the molecular formula?
A compound is found to contain 64.80 % carbon , 13.62 % hydrogen , and 21.58 % oxygen by mass. the empirical formula is? the molar mass is 74.14 g/mol, what is the molecular formula?
1)
we have mass of each elements as:
N: 63.65 g
O: 36.35 g
Divide by molar mass to get number of moles of each:
N: 63.65/14.01 = 4.543
O: 36.35/16.0 = 2.272
Divide by smallest to get simplest whole number ratio:
N: 4.543/2.272 = 2
O: 2.272/2.272 = 1
So empirical formula is:N2O
Molar mass of N2O,
MM = 2*MM(N) + 1*MM(O)
= 2*14.01 + 1*16.0
= 44.02 g/mol
Now we have:
Molar mass = 44.02 g/mol
Empirical formula mass = 44.02 g/mol
Multiplying factor = molar mass / empirical formula mass
= 44.02/44.02
= 1
So molecular formula is:N2O
Answer: N2O
2)
we have mass of each elements as:
Si: 6.36 g
Br: 36.18 g
I: 57.46 g
Divide by molar mass to get number of moles of each:
Si: 6.36/28.09 = 0.2264
Br: 36.18/79.9 = 0.4528
I: 57.46/126.9 = 0.4528
Divide by smallest to get simplest whole number ratio:
Si: 0.2264/0.2264 = 1
Br: 0.4528/0.2264 = 2
I: 0.4528/0.2264 = 2
So empirical formula is:SiBr2I2
Molar mass of SiBr2I2,
MM = 1*MM(Si) + 2*MM(Br) + 2*MM(I)
= 1*28.09 + 2*79.9 + 2*126.9
= 441.69 g/mol
Now we have:
Molar mass = 441.7 g/mol
Empirical formula mass = 441.69 g/mol
Multiplying factor = molar mass / empirical formula mass
= 441.7/441.69
= 1
So molecular formula is:SiBr2I2
Answer: SiBr2I2
3)
we have mass of each elements as:
C: 64.8 g
H: 13.62 g
O: 21.58 g
Divide by molar mass to get number of moles of each:
C: 64.8/12.01 = 5.3955
H: 13.62/1.008 = 13.5119
O: 21.58/16.0 = 1.3487
Divide by smallest to get simplest whole number ratio:
C: 5.3955/1.3487 = 4
H: 13.5119/1.3487 = 10
O: 1.3487/1.3487 = 1
So empirical formula is:C4H10O
Molar mass of C4H10O,
MM = 4*MM(C) + 10*MM(H) + 1*MM(O)
= 4*12.01 + 10*1.008 + 1*16.0
= 74.12 g/mol
Now we have:
Molar mass = 74.14 g/mol
Empirical formula mass = 74.12 g/mol
Multiplying factor = molar mass / empirical formula mass
= 74.14/74.12
= 1
So molecular formula is:C4H10O
Answer: C4H10O
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