Question

18) A compound is found to contain 22.6% Nitrogen and 77.4% Oxygen. What is the empirical formula of the compound? What is the molecular formula of the compound if its molecular weight is 248g/mole?

Answer 1

% os N = 22.6 % = 77.4% % of grams of N = 22.6.9 grams of o 77.49 ci moles of 'N = 22:6g 14 gimol moles of N 16142 mol moles of o = 77:4 16 g/mol = 4.8375 mol Here N used as reference. . Relative moles of N N=116142 = 1 1-6142 Relative moles of o 4,8315 - 3 116142 Empirical Formula : NO3

n Molecular mass empirical formula mass n = 248 g/mol 14+ 16X3') g/mol Qu8 62 n 4 Now Molecular formula =nx Empirical formula 4 (103) Molecular formula Molecular formula N4012