Q2.
MW of Silver = 107.8682 g/mol
MW of Nitrogen = 14 g/mol
MW of Oxygen = 16 g/mol
so..
assume a basis of 100 g
so
63.5 g of Silver, 8.2 g of N, 28.3 g of O
mol of Ag = mass/MW = 63.5/107.8682 =0.588681 mol
mol of N= mass/MW = 8.2/14= 0.5857 mol
mol of O= mass/MW = 28.3/16=1.76875 mol
ratio is:
1.76875/0.588681 = 3
Ag:N:3O
Empiricla formula:
AgNO3
i.e.
Silver Nitrate
The percent composition of a compound was found to be 63.5 % silver, 8.2 % nitrogen,...
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