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How many grams of iron are needed to completely consume 16.6 L of oxygen gas according to the following reaction at 25 °C and
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Answer #1

2 Fe (5) + O2c9) -> 2FeO (5) Ait STP, I mole of any gas = 2204 L of that gas .: 16.6 L of Og gas = 716-6*!) mole of 0.2 22.47

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