Question

QUESTION 13 Each of the following quantum number sets is supposed to specify an orbital. Select all of the following sets of quantum numbers that contain an error -2.1-1.mp3 - 1.1 -0. m -0 3.1-3. m-2 On-41-2 mi-o on-si-a mi-o

Answer 1

n- Principal quantum number 0 e orbital quan toom number Azimutol quantum number # Magnetic quorum number ms - spin gcantum number n bas values 1,2, 3, 4 ... I has me has Values 0, 1,2,3, n-1) values-1, -1, o,+1... + valuex + 1 & 2 ms has IT n=1 i o te has one value m, - - l to the totoo m +o na 2 moal to to take highest value ~, o,+1 7 3 value for me Actual me has 20th valuex.

op n = 3 m = -2 to +2 7-2, 1, 0+1 +2 20+1 = 2 023+1= 5 valuex. i n=4 = 0, 1, 2, 3 mo= 3 to +3 -3, 2, 1, 0, +1, +2 & 2(3)+ 6+1= 7 valuer 2 1+1= that has If you observe the max no value equal to 2 nal, eo but not i n=2 t ot but not a n=3, t= 0, 1, 2 but not 3 n=4 1= 0, 1, 2,3 but not a so I shouldn't have value equal to n Value of d f value of n

3 Let us consider each option option m2, el.me - 3 contour me = -1 tot 71, 0, 1 there por n=2, e=1 correct bust me 3 not exista so wrong This option controns e n me 31 m oto to so all are corint s. This contains no eranr. 3 = 3 mp -2 contrin Entry for n= 3 me: - to +2 = -2, -,, +1, +2

here, Giners that for n= 3 8 = 3 me- contain not exist exist error/ so this as set l=3 for n=4 e = 0, 1, 2, 3 me -3 to +3 y 3, 2, 1, 0, +1, +2, +3 so this set has no error) on=5, 1:0, mezo For na 5 e = 0, 1, 2, 3, 4 my -y to ty -4,3,2,1,0,1, +2, +3. +4 +5 has no error so this set