Number of moles of Fe = 16.3 g / 55.845 g/mol = 0.292 mole
Therefore, the actual yield of Fe = 0.292 mole
From the balanced equation we can say that
1 mole of Fe2O3 produces 2 mole of Fe so
0.247 mole of Fe2O3 will produce
= 0.247 mole of Fe2O3 *(2 mole of Fe / 1 mole of Fe2O3)
= 0.494 mole of Fe
Therefore, theoretical yield of Fe = 0.494 mole
percent yield = (actual yield / theoretical yield)*100
percent yield = (0.292 / 0.494)*100
percent yield = 59.1 %
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19-KOBKO Activities and Due Dates Topic 14 Skills Practice Video E Hint Check Resources nment Score: 0/300 Question 2 of 3 Consider this reaction involving an unknown element X F, +2XBrBr, + 2XF When 1.900 g of XBr reacts, 0.7134 g of Br, is produced. Calculate the molar mass of X, and then identify its element symbol. element symbol for X: g/mol molar mass of X: contact us help terms of use privacy policy about u careen MacBook Air 888...
WILL Submit All Questions Completed 5 out of 11. Save Answer KY mplete < Question 6 of 11 > Combining 0.318 mol Fe,O, with excess carbon produced 17.6 g Fe. mplete Fe, O,+3C-2 Fe +3 CO mplete What is the actual yield of iron in moles? mplete mplete actual yield: mol What is the theoretical yield of iron in moles? theoretical yield: mol What is the percent yield? % percent yield: privacy policy terms of use help contact us about...