At time 13, observed was (1,3,7)
At time 84, observed was (23, -5, 10)
At time 50 , What are the positions observed?
Change in position from 13 to 84 is (22,-8,3) so velocity will be cange in postion divided by change in time and here time t=71 sec
So V = (22/71, -8/71,3/71)
Now at 50 change in time is 50-13= 37
So position at 50 = (1,3,7) +V×37
= (1+11.46, 3-4.17,7+1.56)
= (12.46,-1.17,8.56)
Solved
At time 13, observed was (1,3,7) At time 84, observed was (23, -5, 10) At time...
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