Question

Question 2 of 3 Two reactions and their equilibrium constants are given. A+2B 2C K1 2.77 2C D K2 0.198 Calculate the value of the equilibrium constant for the reaction D A + 2 B. K =

Answer 1

Question 2 for this type of prooblem we have to remember the following poi- nts - On roeversing an equilibrium reaction, we get a new roate constant which is reciprocal of the former . i when we add to equilibrai- um reaction to get the new equilibrium constant we have to multiply the equilibrium const- aut for each of the reaction. Now, here given that - A + 2B 20 k, = 2.77 20 - K₂=0.198 Now adding these two reaction we get, - A + 2B FDK' =k, XK₂ = 2.77 x 0.198

Again, beversing the above equation we get, - D = A + 2B ; k = 1 1 1 ink= 7.77 +0.198 = 3.65 (three sig. nificant figures)