Consider the following reaction: 2 HCl + CaCO 3 → CaCl 2 + H 2 O...
Consider the following reaction: 2 HCl + CaCO 3 → CaCl 2 + H 2 O + CO 2
How many mols of calcium chloride can be produced if you begin with 7.49 mL of 0.62 M HCl and 12.26 grams of calcium carbonate? Record your answer in scientific notation, using 3 significant figures.
Homework Answers
Moles of calcium carbonate used = mass/molar mass
= 12.26/100.08 = 0.1225 moles
Moles of HCl = molarity×volume/1000
= 0.62×7.49/1000 = 0.00464 moles
According to the reaction,
2mole HCl require 1 mole CaCO3
0.00464 moles of HCl require 0.00464/2 moles CaCO3
= 0.00232 moles CaCO3
We have more than this CaCO3 hence HCl is limiting reagent.
According to the reaction,
2 mole HCl give 1 mole CaCl2
0.00464 moles HCl give 0.00464/2 mole CaCl2
= 0.00232 moles CaCl2
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