Question

cion 1 of 3 > When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. Caco, (s) + 2 HCl(aq) - CaCl, (aq) + H,0(1) + CO,(8) How many grams of calcium chloride will be produced when 31.0 g of calcium carbonate is combined with 10.0 g of hydrochloric acid? mass of CaCl Which reactant is in excess? OHCI OCaCO, How many grams of the excess reactant will remain after the reaction is complete? mass of excess reactant: Question Source: MRG - General Chemistry blisher:

Answer 1

Ø when calcium carbonate is added to hydrochloric acid, calcium chloride, Carbon-di-oxide, and water are produced The balanced chemical equation can be written as, caco 315+ 2 hcecay = cacl gaut H20 @ + O2@. 3.og 10.0g - To find limiting reactanto - To convent into moles of each reactant Molar holar mass of mass of cacoz = 100.08 g/mol stel - 36.46 glmal 31.0g cacos x 1 mol catoz Ісъ - o8 Acatoz 3 0.3097 mole cacoz mole stel 100g Hel x 1 mol tee = 0.2 742 36.46 ghee Stoichio metric ration 0.3097 mole cacoz & I reaction 1 mole cacaz 0:2742 mole stel & 1 reaction 2 mole sice = 0.3097 - 011371 На so 0.1371 0.3097 Cacos wel will be limiting reactant. Cacoz will be excess reactant, and

Another approach. To called ate minimum grams or moles of one reactant hee ded to completely consumed a second reactant It the available amount of roactant A' exceeds What is needed, then it is encess reactant, if not, then the reactant B will be - limiting reactant. limiting cacoz (s) + 2 Hel (aa) Calle Can & stores 310g 1000g starting with cacoz we calmlate minima grams of the needed to completely consumed i 31.0 g ca coz 31-o g cacoz & Imole calz -=0.3097 mole catez - 100.0f mole cacos : 0.3097 mole Caco 3 x 2 role stel 36.46 g Heu 1 mole cacos Imole Hel & COCO But arailable 1000g Ace a railable to a than the 22.587 g oi He needed. so stel will be limiting, reactant and Cacoz will be excess reacta = 29.5 819 Hel to us, is less & The e encess ex reactant is o Ace o cacoz 7 Gerams of cada produced- 10.0 g Hux Imolend 1 mole cach, 110.98 of calle 36.46 g Hee 2 more tee 1 mole cache = 15.2194 gcae " ' Molar cach mass of = 110.98 glomal) Gerams of alma alle formed - (15:194 lg formed

- Gerams of excess nemains after complete the reaction a starting with Hel, we calculate minimum grams of cacoz needed to completely consumed the 100 g tee hore the Imole cacoz 100.08 g Cacoz 1 oro gta 36.46 gtce a mole Hel* I mole caloz 13.7245 But geacoz to ne more than the 13.721 la Tu arailable Q 31.0 g caug arailable than the 13.7246 g lacos needed. to us, is smass of excess after complete the ains reactant remains reaction. (z. action- (31.0-13-72616) = 17.245319