Question

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. CaCO3(s) + 2 HCl(aq) +CaCl, (aq) + H2O(l) + CO2(g) How many grams of calcium chloride will be produced when 30.0 g of calcium carbonate is combined with 11.0 g of hydrochloric acid? mass of CaCl2: Which reactant is in excess? OHCI O Caco How many grams of the excess reactant will remain after the reaction is complete? mass of excess reactant:

Answer 1

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Cacoz (s) + 2 HCl (aq) → Cally cag+ H200+ (0,(9) CaCO3 i 30g & molar mass = 100 g/mol # no. of moles = mass (9 309 molar mass (g/mol) HU: 'g ; molaur mass = 36.5 g/mol # no. of moles = 11.og 100 g/mol = 0.3 mof 36.5 g/mal = 0.301 mot from equation, Imol Caco reacts with 2 mol fel. So, 0.30 mo call rearts with a mot Hel = 0.30 ml x 2 mol Imol = 0.60 mot of rell is required But thuѕ ѕо. us 0.301 mol HCl only, which is not enfficient. There fore file is limiting reactant caco, is excess reactant Now I mot Hill reacts to produce I mot call So, 0.301 mol Hel reacts to produce – mol Calla - 0-301 ml x 1 mol I = – 0.1506 mol of Calla - 2 mol Mass of calls = no. of moke & molar mass = 0.1506 molx 110,98 g/mol = 16.72 g of Calla will be produced when a mol of Hill rearts with (mol caco 0.301 mol Hll reacts with a nd Cacoz I J=0-1506 ved & Out of 0.30 most of laco -0.1506 mol of laco, is reacted and remaining o-goma-0.1506 and = 0. 1494 and of caca mass of Etreces Cacoz = 0.1494 mol x 100g/mar = 114.94 gf of lacoz will be left- 1.301X