Question

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. CaCO3(s) + 2 HCl(aq) — CaCl2 (aq) + H2O(1) + CO2(g) How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate is combined with 13.0 g of hydrochloric acid? mass of CaCl2: 8 Which reactant is in excess? OHCI Caco, How many grams of the excess reactant will remain after the reaction is complete? mass of excess reactant:

Answer 1

Sol CaCO₃ + 2H U Calla + H₂O + CO₂ 36.5 Moles of Caloz= mass - 29 - 029 moles. MolerMass Moles of HU 13 = 0.3562 moles. from Reactions 2 mole Hll requines I mole CaCO3 .: 0.3562 n n = 0.3562 = 0.1781 moles of CaCO3 Available moles of CaCO3 > Required mobs of CaCO3 Hence, Calos is excess reagent and Hill is limiting reagent Remaining moles of CaCO3 = unreacted moles of laco As = 0.29 - 0.1781 = 0.1919 moles, Mass of CaCO3 remaining = mols moler mas = aill19 x 100 = 11.19 grans. As Again from reactions a mole He produce I mole Calle 10.3562 - 0:3562 2 = 0.1781 mols of Colla 0,1781 maledicco Mass of Calla produced = moles x moler mas = 011781 x 1 = [ 19.77 grans. An

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