Question

dunal, But only over a part of the domain. The reason why it is useful to assume a local constant rate of change is because then the changes in the quantity's measures are proportional. In Problems 4 and 4, you assumed that the output quantity varies at a constant rate with respect to the input quantity, and used the proportionality in the changes in the quantity's measures to approximate the output values associated with particular input values. As you wi see in the next investigation, assuming a local constant rate of change is useful for determining the rate at which the output quantity changes with respect to the input quantity at a specific value of the input quantity ll Homework 1. Suppose you deposit $1,500 into an account at the Fine Bank of Murfreesboro on August 1, because the account value increases continuously for all student accounts. You are very disciplined and don't withdraw any money from your account for five months. The following is a table of values showing the amount of money in your bank account at the end of each of those five months. Date August 31 September 30 October 31 November 30 December 31 | $1,505.46 Account Valuei s 1,502.73 | $1,508.20 | $1.510.94 Isl,51369 Does the account value vary at a constant rate with respect to the number of months elapsed since August 1s? Explain. Approximate how much money is in your account on October 7h. Explain how you computed your approximation. a. b. c. Approximate how much more money there is in your account on November 13h than there is on November 5h. Explain how you computed your approximation. 2. A car's distance past a stop sign increases according to the function s defined by s()-2 where represents the number of seconds elapsed since the car started moving and s() represents the car's distanc (in feet) past the stop sign. a. What is the average rate of change of the car's distance past the stop sign as the value of f increases from 3 to 10 26 Pathways Through Calculus 0 2016 Tallman, Carlson, and Hart

Answer 1

Solution

No the return is not constant. Calculation is given below:

Date	Account value	Interest amount	Rate of return
01-Aug	1,500.00
31-Aug	1,502.73	2.73	2.2143%
30-Sep	1,505.46	2.73	2.2143%
31-Oct	1,508.20	2.74	2.1508%
30-Nov	1,510.94	2.74	2.2224%
31-Dec	1,513.69	2.75	2.1586%
	Account value	Interest amount
30-Sep	1,505.46
07-Oct	1,506.08	0.62		account value on 7th oct
31-Oct	1,508.20	2.12
05-Nov	1,508.66	0.46
13-Nov	1,509.39	1.19	0.73	account value increase by 73 cents from 5th nov to 13th nov