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Question 2 (20 martos) The maintenance manager of a manufacturing company is attempting to estimate the likely trage of a par

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Answer #1
A B=A-39 C=B^2
Units Deviation from Mean Deviation Squared
January 20 -19 361
February 30 -9 81
March 25 -14 196
April 40 1 1
May 50 11 121
June 42 3 9
July 37 -2 4
August 65 26 676
September 49 10 100
October 27 -12 144
November 53 14 196
December 29 -10 100
Total 467 1989
Arithmatic Mean=Total/(Number of records)
Arithmatic Mean=467/12 39
Variance =1989/(12-1) 180.8181818
Standard Deviation = 13 Square Root of (180.8182)
Median:
Arrange in descending order:
Units
65
53
50
49
42
40
37
30
29
27
25
20
Meadian is the middle value
Meadian =(40+37)/2 39
Range =Difference between maximum and minimum
Range =65-20 45
These data helps the manager in planning , arranging resources, because he will know the range ,mean ,median and standard deviation of requirenent

ACTION: Build Small Facility: Demand Low High Probability Outcome 0.6 £ 700,000 0.4 £ 520,000 Total £ 628,000 Probability* Ou
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