please write neatly. Thank you 28. Two charges, -q and -3q, are separated by a distance...
18. (III) Two charges, -Q and -3Q, are a distance l apart. These two charges are free to move but do not because there is a third (fixed) charge nearby. What must be the magnitude of the third charge and its placement in order for the first two to be in equilibrium?
Two particles with charges +2q and -q are separated by a distance of 0.25 m. If a third particle with charge -3q be placed at the midpoint between the first two particles, what is the magnitude of the net electric force on the particle?
P3. (a) Consider two charges, held a fixed distance apart, as shown. Where should a third charge q be placed so that it experiences no net force? Explain why your answer does not depend on the sign or the magnitude of q 3Q (b) For the two charges shown, determine where a third charge q should be placed so that it experiences no net force 3Q
Please show all work and steps! 4. Two charges, +3Q and -Q, are separated by 4 cm. Is there a point along the Region I Region I1 Region III line passing through them (and a finite distance from the charges) where the net electric field is zero? If so, where? How about any location that is not collinear with the charges. +30 -0
Consider two negative charges, -/q/ and -/3q/ , held fixed at the base of an equilateral triangle with side length s. The remaining vertex of the triangle is point P. A.) what is the potential energy of this system of two charges? B.) What is the electric potential at point P.? C.) How much work will it take (similarly, what will the change in electric potential energy of the system) to bring a third negative charge (-/q3/) to point P...
Coulomb's law for the magnitude of the force Fbetween two particles with charges Q and Q′separated by a distance d is |F|=K|QQ′|d2, where K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q1 = -10.0 nC , is located at x1 = -1.750 m ;the second charge, q2 = 32.5 nC , is at the origin (x=0.0000). What is the net force exerted by these two charges on a third charge...
Coulomb's law for the magnitude of the force Fbetween two particles with charges Q and Q′separated by a distance d is |F|=K|QQ′|d2, where K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q1 = -19.0 nC , is located at x1 = -1.715 m ; the second charge, q2 = 35.0 nC , is at the origin (x=0.0000). What is the net force exerted by these two charges on...
Two point charges q and ?q are separated by a distance L. What is the magnitude of the force on a third point charge q placed at the midpoint between them? (a) 8kq2/L2 (b) 2kq2/L2 (c) 0 (d) 4kq2/L2 (e) kq2/L2 any explanation is helpful!
A particle with charge q is located at the origin, and a particle with charge 3q is on the positive x axis, a distance d from the origin. The particles are not free to move. In terms of q and d, at what coordinates should a third particle with charge q be placed so that it experiences no net electrostatic force? (Assume r is the location of the third particle away from the origin, along the positive x axis.) r=
Coulomb's law for the magnitude of the force Fbetween two particles with charges Q and Q′separated by a distance d is |F|=(K|QQ′|)/d2, -----------> (side note: those are absolute bars on the QQs where K=1/(4πϵ0), and ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q1 = -10.0 nC , is located at x1 = -1.660 m ; the second charge, q2 = 35.5 nC ,is at the origin (x=0.0000). Question: What...