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Two particles with charges +2q and -q are separated by a distance of 0.25 m. If a third particle with charge -3q be placed at the midpoint between the first two particles, what is the magnitude of the net electric force on the particle?

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Answer #1

net force on given charge

F = k q3 q1 / r^2 + k q3 q2 / r^2

F = 9*10^9* (3q) * [ (2q) / 0.25^2 + q/ 0.25^2 ]

F = 1.296*10^12 q^2

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do comment in case any doubt, will reply for sure. Goodluck

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