Question

A 30.0 L vessel contains a mixture of carbon dioxide, sulfur trioxide, oxygen, and neon gases at 25.0°C and 2.75 atm. The mole fraction of each gas is 0.25. What mass of each gas is present? Answer 2. Fluorine diffuses 3.45 times faster than gas Q. Calculate the molar mass of gas Q. Answer 3. 1.500 g of a gas collected over H.O at 29.0°C and 740.9 mm Hg occupies a volume of 217.2 mL. The vapor pressure of H.O at 29.0°C is 30.0 mm Hg. What is the molar mass of the gas? Answer 4. What volume of NH, (measured at STP) can be produced by reacting 8.51 liters (STP) N, with 3.15 x 10” molecules H,? Write the balanced equation. Answer

Answer 1

Volume of vessel (V) = 80L Temperature (T) = 25°C = 273+25 T = 298k (intel CORE Total pressure of mixture (P) = 2.75 atm ideal gees Equation PV = nRT P= Pressure of solution V= Volume n= no. cf moles R = gas constant (0.082 2-alm! T= Temperature Komal (2.750tm)*(30) - * (0.0821)*(298) - n = 3.37 mole Total moles of goses. given mole fraction of each = 0.25 mole fraction= no. of moles Totalmoles = mole fraction of co2 = 0.25 moles of co2 Totalmoles moles of con 0.25= 3.37 moles of Co2 = 0.25% 3.37 = 0.84 moles =

molar mass of coa = 12+10*2 =499/mole moles = mass Metar mass mass of co2 0.84 moker mass of coa = mass of coa = 0.84* 44 = 36.96gm. 37 gm Similarly moles of suffer mele fraction of Sulfur trioxide (S03) - Tot cel yoles moles of sulfur 0.25 = 3.37 moles of selfer" = private 0.84 moles moles of oxygen = 0.84 moles mole of Meen = o.su mole. Molas mass of soz= 324 16*3= 80g/mole molar mass of O2 = 32 g/mole molar mass of Ne=20 g/mole mass of son moles of Sort Molarmass 0.84x80 = 67.2 gm mass of O₂ = 0.84*32 = 26.88gm mass of Me= 0.84*20= 16.8 gm