Question

A 1.10 kg sample of a metal sample absorbs 43.5 kJ of heat, resulting in a...

A 1.10 kg sample of a metal sample absorbs 43.5 kJ of heat, resulting in a temperature rise of 65.0 °C. What is the specific heat capacity of the metal?

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Answer #1

Given:

Q = 43.5 KJ = 43500 J

m = 1.10 Kg = 1100 g

ΔT = 65 oC

use:

Q = m*C*ΔT

43500 = 1100.0*C*65.0

C = 0.608 J/g.oC

Answer: 0.608 J/g.oC

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