If a sample of water absorbs 41.0 kJ of heat and the temperature of the sample...
If a sample of water absorbs 41.0 kJ of heat and the
temperature of the sample changes from 25.0∘C to 56.0∘C, what is
the mass of the sample in grams?
Remember that the specific heat capacity of water is
4.184Jg⋅∘C.
Homework Answers
q = 41Kj = 41000J
t1 = 250C
t2 = 560C
c = 4.184J/g-0C
q = mc
t
41000 = m*4.184*(56-25)
m = 41000/(4.184*31) = 316.1g
mass of water = 316.1g >>>>answer
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