Question

A 350.0 gram sample of copper is initially at 25.0C. If the sample absorbs 12.50 kJ of heat from its surroundings, what is its final temperature? cs(Cu) = 0.386 J/g°C

Answer 1

The amount of heat absorbed , Q = mcdt

Where

m = mass of copper sample = 350.0 g

c = specific heat capacity of copper = 0.385 J/goC

dt = change in temperature = final - initial

   = t - 25

Q = heta absorbed = 12.50 kJ

                            = 12.5x1000 J

                            = 12500 J

Plug the values we get

12500 = 350 x 0.386 x (t-25)

t = 117.5 ^oC

Therefore the final temperature is 117.5 ^oC