Question

I just dont know if these are right. Any help is much appreciated!

Compare the size of I and I: I has the same number of protons and more electrons compared to I. For this reason, l'experiences a lower Zeff which makes the ion larger in size compared to l. Question 10 0.15 pts Compare the size of Ca2+ and K+: Ca2+ has more protons and the same number of electrons compared to K+. For this reason, Ca2+ experiences a lower Zeff which makes the ion larger in size 9 compared to K+.

Answer 1

ar el l and I 1 Atomic Number -53 (Z). 2 mass Number = 127 I I Proton Number = 53 53 Election Number = 53 53+1=54 Becaue P/E Ratio will be different in I In and less pt as compared to é in I that's why. I. Experience lower (tre) effective muleer Nuclear Charg (Zeff) Atomic No Same No of Roton] 20 TQ-10 Tpt I e- Ca 2+ = 20 10 (2) (k+ 19 18 Imore Election 19 A lower eft larger size ca²t experience more Zeff (20p) as compared to kt (Zeff = 19pt) the same No of et more Number of Proton Thankvery much Hope this will help hla Smaller in Size you good luck