Question 1 2C8H18 + 2502 - 16CO2 + 18H20 AH rxn--11020 kJ/mol rxn Look at above...

Question

Question

Answer 1

Answer #1

Answer:

Step 1: Calculate the moles from mass

We know, moles = mass / molar mass

moles of C₈H₁₈ = 7 g / 114.23 g/mol = 0.06128 mol

Step 2: Calculation

(1) Write the equation

2 C₈H₁₈ + 25O₂---> 16CO₂ +18H₂O ; ΔH=−11020 kJ

For 2 moles of C₈H₁₈ enthaply released = 11020 kJ

so, for 0.06128 mol of C₈H₁₈ enthapy released will be = ( 11020 kJ / 2 mol ) × 0.06128 mol = 338 kJ

Hence the enthalpy released = 338 kJ -----option(8) (last one)

Answer 2

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