Question

1. Two fifth-period atoms, one of a transition metal, M, and the other of a main-group nonmetal, X , form a compound with the formula M2X3 . Enter answers with noble-gas core, that is, an inner-shell configuration corresponding to nearest noble gases, plus outer electrons.

What is the electron configuration of atom X if M is Ru ?

(Express your answer in condensed form, in order of increasing orbital energy.)

What is the electron configuration of atom X if M is Rh ?

2. Using the periodic table, Arrange each group of anions in order of increasing ionic radius.

a. P3-, Cl-, S2-

b. Cl-, I-, Br-

Answer 1

E a) Mara a) M is Ru = [kr34d'ss' Valenty of M= 3 Valery of x =2 5th penod main group non metal :.XI = [K, J4d "55585 4 Iodine b) I mis Rh = [kr] låss! 45 In 5th Penod, there is only I main group no metal is lodric .:8= 1 = (ker]4d55²505 p = 18 licetrons cí = 18 elections Ⓡua 52 = 18 elections on moving from left to right in a periodic table wonie radie durcares because nuclear attraction felt by é increases & atoms become more compact . 1. Ionie radie - p3<5²-26) ® é I on moung from top to bottom in a groy, a new Shell is added in each group iconic radi is I J ( Ionie radici (BrcI