can you please explain this question with detailed explanation and background theory both? 246:43 112 59424...

Question

Question

can you please explain this question with detailed explanation and background theory both?

Answer 1

Answer #1

Reaction known as ozonolysis.

Mechanism -

(43 СН2 IN 13-dipolar spaltung 1,3-dipolar addition Primary ozonide (H₂-CHO ZnH2O + Zno ozonide in the presence of an further NOTE-:

H2O2 is a oxidizing agent.

So option F will be correct option.

Answer 2

Similar Homework Help Questions

can you please explain this question with detailed explanation and background theory both? 51% 246:33 119...

can you please explain this question with detailed explanation and background theory both? 51% 246:33 119 59221 х chapter_11_powerpoint_1.ppt Determine the product. HzC CH2 1)HC=C 2) H20 B. HC OH HH
can you please explain this question with detailed explanation and background theory both? 48% 246:42 119...

can you please explain this question with detailed explanation and background theory both? 48% 246:42 119 59221 X chapter_12_powerpoint_1.ppt Determine the product. CH3CH2OH K2Cr207 H SO, A brando CH, B. che Hic HC OH D. None of these
can you please explain this question with detailed explanation and background theory both? 51% 246:33 119...

can you please explain this question with detailed explanation and background theory both? 51% 246:33 119 59221 x chapter_11_powerpoint_1.ppt What is the starting material in the reaction below? U NH T CH:CH-CH,CECCH CH; LAAT B.B c.c

can you please explain this question with detailed explanation and background theory both? 246:34 11259624 51%...

can you please explain this question with detailed explanation and background theory both? 246:34 11259624 51% chapter_11_powerpoint_1.ppt Determine the product. [1] NaNH2 CH3CH2C=CH 1210 CB Br B.CH3CH2-CEC-CH CH2CH2-C=C-CH NH2 D. E. None of these -Br
can you please explain this question with detailed explanation and background theory both? 51% 246:34 11959...

can you please explain this question with detailed explanation and background theory both? 51% 246:34 11959 29 x chapter_12_powerpoint_1.ppt What is the starting material in the reaction below? (1) Hz/Lindlar [2] CI2 HH CH3CH2-.--CHz A. CH2CH=CHCH=CH, B. CH:CH=C=CHCH; C. CH3CH2CH2C=CH D. CH3CH2CH2CH=CH, E. CH3CH2C=CCH3 |
can you please explain this question with detailed explanation and background theory both? 2 6:43 11...

can you please explain this question with detailed explanation and background theory both? 2 6:43 11 5 2 48% chapter_12_powerpoint_l. ppt X Determine the product. CH3 CH3COOH 10 A. B. C. D. OH OH F. all of the above E. A and B

can you please explain these 2 questions with detailed explanation and background theory both? 2 6:35...

can you please explain these 2 questions with detailed explanation and background theory both? 2 6:35 11 5 R 51%1 chapter_12_powerpoint_I. ppt What is the product of reaction below? 1) CH COH 2) -Он/н-0 но, Е. но. но В. A. но но но Determine the product. mCPBA Н н OH он он Нас. CHs C Н,с- CH3 Нас-сн D. A. H3C CH B н н Н Н E. none of the above
can you please explain this question with detailed explanation and background theory both? 27 6:34 119...

can you please explain this question with detailed explanation and background theory both? 27 6:34 119 5928 51% chapter_12_powerpoint .ppt What is the degree of unsaturation of C7H6BrNO? A. 3 B.4 4.5 5.6 E. 7
can you please explain this question with detailed explanation and background theory both? When a compound a with mo...

can you please explain this question with detailed explanation and background theory both? When a compound a with molecular formula C12H12 is treated with excess H2 in the presence of Pd, a compound having molecular formula C12H20 is formed. How many rings and double bonds does compound possess? A. No rings and 5 double bonds B. 3 ring and 4 double bonds C. 2 rings and 3 double bonds D. 4 rings and 2 double bonds E. None of these...

Can you explain this in very much detail including background theory and things I have to...

Can you explain this in very much detail including background theory and things I have to know to solve this? What is the product? H2SO4 CH3 H нус-с-с-сң CH, OH А. сн. н в. в не сн с. нс. н. с-с-сн, р. A and в E. B and C нэс-с-с-с-н нс сн ныс сн. сн,