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Given the following data and information: (1) 2B + 3/2 02 (9) ---> B2O3 delta H = -1264 kJ (2) 2B + 03 (g) ---> B203 delta H
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Answer #1

< b + 3 од — В,0, АИ = -1 24 ЧkТ В + O2 (а) — В2 02 эди - - 106k

opposite signna reversing eqn @, Al will have now. Be —2B+ 03 (9) Ax=+1406kg

- Adding © ¢ ® on 38 +20,— B603) - 1264 B20₂ 26+ O₂ + 1406 302 → 03 04=+142 A4 =+ 142

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