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pop. mean = 94.98
Ho: Mu = 94.98
Ha: Mu != 94.98
The null hypothesis in words would be:
4th option is correct:The average price of all textbooks from the
store is $94.98
Also given is :
n = 190
Sample mean = 95.78
Stdev =28.2
Point estimate= sample mean ( because the sample mean is a unbiased estimator of pop. mean ) = 95.78
The 90% Confidence interval is : 1.645
So, 90% CI is 94.98 +/- 1.645*28.2/sqrt(190)
= 91.615 to 98.345
Since the sample mean (of 95.78) lies between the 90% Confidence interval ( 91.615, 98.345) we conclude that we fail to reject the null hypothesis
Suppose that BC financial aid alots a textboolk stipend by claiming that the average textbook at...
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