Question

A satellite in low Earth orbit is 225km above the surface. What is its orbital velocity....

A satellite in low Earth orbit is 225km above the surface. What is its orbital velocity. Mass of earth= 6 x 10^24 kg. Radius of earth = 6.38 x 10^6m

0 0
Add a comment Improve this question Transcribed image text
Answer #1

radius of orbit , r = radius of earth + height

r = 225 + 6380 = 6605 km

speed of satellite , v = sqrt(G * m/r)

v = sqrt(6.673 *10^-11 * 6 * 10^24/(6605 *10^3))

v = 7785.7 m/s

the speed of the satellite is 7785.7 m/s

Add a comment
Know the answer?
Add Answer to:
A satellite in low Earth orbit is 225km above the surface. What is its orbital velocity....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A satellite is launched to orbit the Earth at an altitude of 3.45 x 10^7 m...

    A satellite is launched to orbit the Earth at an altitude of 3.45 x 10^7 m for use in the Global Positioning System (GPS). Take the mass of the Earth to be 5.97 x 10^24 kg and its radius 6.38 x 10^6 m. What is the orbital period of this GPS satellite? With what speed does it orbit the Earth?

  • A satellite is in orbit around Earth at a height of 120 km above Earth’s surface....

    A satellite is in orbit around Earth at a height of 120 km above Earth’s surface. Find the orbital speed of the satellite. (Mass of the earth is 6*1024 kg and the radius of Earth is 6371 km)

  • A satellite is at an altitude of 852 kilometers above the Earth's surface. The mass of...

    A satellite is at an altitude of 852 kilometers above the Earth's surface. The mass of Earth is 5.972 x 10^24 kg and the radius of Earth is 6.378 * 10^6 m. (1) What is the acceleration due to gravity in the orbit? (2) What is the orbital velocity and period of the orbit? (3) Derive the equation for the escape velocity of the orbit and provide the numerical value.

  • a satelite is in circular orbit 230km above the surface of earth. if the mass of...

    a satelite is in circular orbit 230km above the surface of earth. if the mass of the earth is 5.98 x 10^24 kg and the radius of the earth is 6.38 x 10^6 m what is the time pe

  • A satellite is launched to orbit the Earth at an altitude of 2.85 times 10^7 m...

    A satellite is launched to orbit the Earth at an altitude of 2.85 times 10^7 m for use in the Global Positioning System (GPS). Take the mass of the Earth to be 5.97 times 10^24 kg and its radius 6.38 times 10^6 m. What is the orbital period of this GPS satellite? With what speed does it orbit the Earth? What distance does the satellite cover in one revolution? m/s

  • 10-3. A 639-kg satellite is in a circular orbit about Earth at a height h =...

    10-3. A 639-kg satellite is in a circular orbit about Earth at a height h = 1.16 x 10^7 m above the Earth’s surface. Find (a) the gravitational force (N) acting on the satellite, (b) the satellite’s speed (m/s) (magnitude of its velocity, not its angular velocity), and (c) the period (h) of its revolution. Caution: The radius of the satellite’s orbit is not just its height above the Earth’s surface. It also includes the radius of the Earth. The...

  • A satellite is launched to orbit the Earth at an altitude of 1.75 x10*7 m for...

    A satellite is launched to orbit the Earth at an altitude of 1.75 x10*7 m for use in the Global Positioning System (GPS). Take the mass of the Earth to be 5.97 x10*24 kg and its radius 6.38 x10*6 m. (a) What is the orbital period, in hours, of this GPS satellite? (b) With what speed, in m/s, does it orbit the Earth?

  • A satellite of Earth is moving in a circular orbit with Earth at its center, at...

    A satellite of Earth is moving in a circular orbit with Earth at its center, at a constant speed of 2.00 km/s. a.) How high is the satellite above the surface of the Earth? b.) How long does it take for the satellite to complete one revolution? Helpful info (but not all of it is relevant!): universal gravitational constant G is = 6.674 x 10^-11 m^3/kg s^2 (units may also be expressed as N m^2/kg^2) Mass of Sun = 1.989...

  • A particular satellite was placed in a circular orbit about 163 mi above Earth. (a) Determine...

    A particular satellite was placed in a circular orbit about 163 mi above Earth. (a) Determine the orbital speed of the satellite. m/s (b) Determine the time required for one complete revolution. min 1024 kg.) An artificial satellite circling the Earth completes each orbit in 119 minutes. (The radius of the Earth is 6.38 x 106 m. The mass of the Earth is 5.98 (a) Find the altitude of the satellite. m (b) What is the value of g at...

  • Derive the "Clarke radius", the altitude above the surface of the Earth where a satellite in a circular orbit h...

    Derive the "Clarke radius", the altitude above the surface of the Earth where a satellite in a circular orbit has an orbital period of exactly one day. Assume a spherical Earth, and use the following constants (taken from Vallado, David A., Fundamentals of Astrodynamics and Applications, 2nd ed. 2001) Gravitational constant: G 6.673 x 10-20 km Radius of the Earth: Re = 6378.137 km 1024 kg Mass of the Earth: Me = 5.9733328 x Round your final answer to four...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT